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777dan777 [17]
4 years ago
11

Simplify rational equations y=x^2+3x/xShow work, please

Mathematics
1 answer:
lora16 [44]4 years ago
7 0

Answer:

6

Step-by-step explanation:

2y x 3x

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What’s the equation for this graph?
harkovskaia [24]

Answer:

y=-3x+2

Step-by-step explanation:

as x goes up on y goes down 3

slope is change in y over change in x

-3/1=-3

the y intercept is (0,2) so the y intercept is +2

8 0
3 years ago
2. Presley graphed a system of equations, and the graph showed two parallel lines. What does this mean? A. The system of equatio
iris [78.8K]

Answer:

B. The system of equations has no solution.

Step-by-step explanation:

Parallel lines never touch, in order for a system of equation to have a solution the two equations have to intersect, because parallel lines never intersect the system of equations that Presley graphed would have no solution

5 0
3 years ago
Read 2 more answers
How to do 3/2b+1/5b=17 ?
guajiro [1.7K]

Answer:

b = 10

Explanation:

Lets start by combining like terms (b):

3/2b + 1/5b

to combine these fractions you must get them to both have the same denominator:

3/2 · 5/5 = 15/10     multiply top and bottom by other fractions denominator

1/5 · 2/2 = 2/10       multiply top and bottom by other fractions denominator

15/10 + 2/10 = 17/10

17/10b = 17

Now we want to get the b to be by itself, so lets first multiply both sides by 10:

17b = 170

Now lets divide both sides by 17:

b = 10

Hope this helped!

7 0
3 years ago
Read 2 more answers
How do you solve <br> 10 squared + 13 squared = c squared<br> (Pythagorean theorem)
alina1380 [7]
10^2 + 13^2 =c^2\\\\100 + 169=c^2\\\\269 = c^2\\\\\boxed{\bf{c=\sqrt{269}\approx 16.4}}
5 0
3 years ago
A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz
marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean,\mu_xis calculated as:

\mu_x=\mu=204.9, \mu_x=sample \ mean

-The standard deviation,\sigma_x is calculated as:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean,\mu_x is calculated as:

\mu_x=\mu\\\\=75.9

#The sample standard deviation is calculated as follows:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

\mu_x=\mu=135.7

#Sample standard deviation:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0
3 years ago
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