Answer:
Add
11 over 2
11 2 + 11 over 4 11 4 = 33 over 4 33 4
Step 1 of 2: Add. Show the work
Step 2 of 2: Simplify.
Simplify
33 over 4 33 4 = 8 and 1 over 48
1
4
Step-by-step explanation:
Answer:
C - 45 is the LCM of 15 & 45
Step-by-step explanation:
Find the multiples:
15, 30, 45, 60
45, 90
They both have 45 in common
Answer:
Step-by-step explanation:

Use the order of operations.
Note: PEMDAS or BODMAS stands for:
<u>PEMDAS</u>
- <u>Parentheses</u>
- <u>Exponents</u>
- <u>Multiply</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>BODMAS</u>
- <u>Brackets</u>
- <u>Order</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>First, do parentheses.</u>
3+6*(5+4)÷3-7
(5+4)=9

<u>Do multiply and divide.</u>
6*9=54
54/3=18
<u>Then, rewrite the problem down.</u>

<u>Add.</u>



- <u>Therefore, the correct answer is "C. 14".</u>
I hope this helps, let me know if you have any questions.
Answer:
![6 \sqrt[3]{5}](https://tex.z-dn.net/?f=6%20%5Csqrt%5B3%5D%7B5%7D)
Step-by-step explanation:
For the problem,
, use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.
![\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%2A%5Csqrt%5B3%5D%7B45%7D%20%3D%20%5Csqrt%5B3%5D%7B24%2A45%7D)
You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.
![\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3} = 6 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%2A45%7D%20%3D%5Csqrt%5B3%5D%7B3%2A8%2A5%2A3%2A3%7D%20%20%3D%206%20%5Csqrt%5B3%5D%7B5%7D)
If I’m not wrong the answer should be 75