<em>x</em> ^2 + <em>y</em> ^2 = 9 => <em>y</em> = <em>y(x)</em> = ± √(9 - <em>x</em> ^2)
Each cross section would be a square with side length equal to the vertical distance between the upper and lower semicircles defined by <em>y(x)</em>, which is
√(9 - <em>x</em> ^2) - (- √(9 - <em>x</em> ^2)) = 2 √(9 - <em>x</em> ^2)
The area of each square section is the square of this length,
(2 √(9 - <em>x</em> ^2)) = 4 (9 - <em>x</em> ^2) = 36 - 4<em>x</em> ^2
We get the whole solid for -3 ≤ <em>x</em> ≤ 3, so integrating gives a volume of

Answer:
0.75
the reason is because if we round it to the nearest tenth . 0.75 becomes 0.8. and 0.075 becomes 0.1 . 0.8 is 8/10th of 1. 0.1 is 1/10th of 1. therefor 0.8 is bigger
Answer:
Carlos is incorrect.
Step-by-step explanation:
We have been given that a line through the origin has a slope of
. Carlos thinks the slope of a perpendicular line at the origin will be 3.
We know that the slope of a perpendicular line to a given line is always negative reciprocal of the slope of the given line.
The slope of the perpendicular line at the origin will be negative reciprocal of
.
Let us find negative reciprocal of
as:

Since the slope of a perpendicular line at the origin is
, therefore, Carlos is incorrect.
#1 is similar to write it out it’s triangle FHG ~ triangle KJL #2 is also but #3 and #4 aren’t
Answer: y = -x + 2
Step-by-step explanation:
When x=0, y = 2
When y=0, x = 2
Hope this helps!