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Varvara68 [4.7K]
3 years ago
6

Suzanne bought a sweater at the sale price of $25. The original cost of the sweater was $40. What percent represents that discou

rage that Suzanne received buying the sweater?
Mathematics
1 answer:
Blizzard [7]3 years ago
5 0
15/40 x 100 = 37.5
equation for percent decrease is diiference/original x 100.
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Alyssa works as a sales representative in an electronics store. She earns a fixed daily wage plus a commission on the sales she
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a) The slope of the line relating Alyssa's sales to earnings is given by 
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Using the first two table entries, the slope is calculated as
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The first entry in the table shows the y-intercept, the value of earnings (80) for zero sales. The slope-intercept form of the equation for a line is
   y = slope*x + y-intercept

To answer the first question, we put the slope and intercept values in the appropriate spots in the equation.

The equation that gives Alyssa's daily earnings based on her total sales is
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b) The y-intercept of the line represents the part of Alyssa's earnings that doesn't depend on sales. It is Alyssa's fixed daily wage.

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d) The y-intercept is 80.
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The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr
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Answer:

(a) E(X) =  0.383

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) P(x = 4) = 0.000169

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$ E(X) =  \frac{n \times r}{N} $

$ E(X) =  \frac{10 \times 8}{209} $

$ E(X) =  \frac{80}{209} $

E(X) =  0.383

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$ P(x = 4) =  \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$ P(x = 4) =  \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{70 \times 84944276340}{35216131179263320}

P(x = 4) = 0.000169

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Step-by-step explanation:

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