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jek_recluse [69]
3 years ago
5

Angles and measurements

Mathematics
2 answers:
Vanyuwa [196]3 years ago
6 0
To answer these questions you would need a protractor
Romashka-Z-Leto [24]3 years ago
5 0
You would need a rainbow shape ruler to answer these angles/degrees
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Whats the value of x? ill give brainliest
NemiM [27]

Answer:

150°

Step-by-step explanation:

180-30=150...............

6 0
3 years ago
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The figure shows a rectangle ABCD.
finlep [7]

Answer:

Answer:

The answer is 39°

Step-by-step explanation:

BAD = 90°

ADE = 51°

AED = 180° - BAD + ADE = 180° - 90° + 51°

= 39°

39° is the Final answer

#AnswerforTrees

3 0
3 years ago
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Do in five minutes please help me out I will give you points if you help me out thank you
Margaret [11]

Answer:

sorry dude no clue

Step-by-step explanation:

8 0
4 years ago
PLEASE HELP, WILL GIVE BRAINLIEST!!!<br><br><br> Find the inverse of f(x)=6x-4<br> and find f^-1(62)
Lena [83]
Answer: 11

=========================

Explanation:

To find the inverse, or f^-1 of a function, you first replace the y= 6x-4 with x=6y-4

Finding the inverse from here is basically just finding y in terms of x.

1) x=6y-4
2) x+4=6
3) (x+4)/6= y

y= (x+4)/6 is now your f^-1.

Now that you have your inverse, replace 62 with your x in y=(x+4)/6

1) (62+4)/6
2) 66/6
3) 11

Therefore, f^-1(62)= 11

Hope this helps :)
5 0
3 years ago
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Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min, and its coarseness is such that it forms a pile in the shap
ikadub [295]

The height is increasing at the rate of (6/5π) ft/min.

It is given that Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min. Also, its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal.

For this, we need to find the volume of a cone. Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

The volume of a cone is - V=1/3hπr²

Learn more about integers here: brainly.com/question/20521181

#SPJ4

4 0
2 years ago
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