Question

How many solutions does a triangle with values a=42, A=117 degrees, and b=34 have?

Answer 1

Answer:one solution

Step-by-step explanation:

Given

a=42

b=34

angle A=117

using sine rule

$\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}$

$\frac{42}{sin117}=\frac{34}{sinB}$

$sinB=\frac{34}{42}\times sin(117)$

sinB=0.7212

$B=46.161 ^{\circ}$

and A+B+C=180

$C=16.839^{\circ}$

Thus 2 triangles can be formed with given value