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Flauer [41]
3 years ago
9

Which is bigger?83 ft or 786 in?

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0
83 FT Because if you divide 786 by 12 (Which is how many inches are in a foot) you will get 65.5 ft.
jonny [76]3 years ago
7 0
Okay so, lets turn 83 feet into inches!
there is 12 inchs in one foot, so we times 83 by 12
83x12= 996 in

996 inches is bigger then 786 inches.
Hope i helped



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Sophie [7]

Answer:

Variant c

Step-by-step explanation:

c²=4*9

c=6

You can apply phyphagor

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3 \sqrt{13}

4 0
3 years ago
Factor x squared-6x+3x-18 by grouping ​
Sindrei [870]

Answer:

(x - 6)(x + 3)

Step-by-step explanation:

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6 0
3 years ago
Carl is going to make a frame for a picture. The dimensions of the frame need to be 2 feet by 18 inches. How long must the board
MArishka [77]
The perimeter of an object is found by adding all of the sides.  The sides of his frame would be 2 ft, 2 ft, 1.5 ft (18 inches / 12 inches per foot = 1.5 feet), 1.5 feet.  Adding these together we get a total length of 7 feet.  However, he may want to use a slightly longer board to account for any errors!
4 0
3 years ago
What is the sum of an 8-term geometric series if the first term is -11, the last term is 859,375, and the common ratio is -5?
NikAS [45]
Formula of the sum of the 1st nth term in a Geometric Progression:


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3 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

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standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
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