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worty [1.4K]
2 years ago
6

Please help me out with this guys. No Links Please!

Mathematics
1 answer:
Sergio [31]2 years ago
5 0
I think it is 29%? I am not 100% sure though...
You might be interested in
Solve<br> 6x−10(x+12)=−4x−24<br> Show your work.
gladu [14]

6x - 10(x + 12) = -4x - 24

<em><u>Distributive property.</u></em>

6x - 10x - 120 = -4x - 24

<em><u>Add 10x to both sides.</u></em>

6x - 120 = 6x - 24

<em><u>Cancel like terms.</u></em>

<em>Add 24 to both sides.</em>

-96 ≠ 0.

This equation is incorrect, as -96 will never be equal to 0.

7 0
3 years ago
PLEASE HELP FAST!!!
Rus_ich [418]

\\ \sf\longmapsto 3s-5+2s+25=170

\\ \sf\longmapsto 5s+20=170

\\ \sf\longmapsto 5s=170-20

\\ \sf\longmapsto 5s=150

\\ \sf\longmapsto s=30

  • m<GHZ=3(30)-5=90-5=85
  • m<ZHI=2(30)+25=60+25=85
4 0
3 years ago
Can someone please help me with this
alexgriva [62]
3 lightest sharks
= 3 3/8 + 3 3/8 + 3 3/8
=  9 9/8
=  10 1/8
7 0
3 years ago
Write a brief explanation on how to simplify radicals
MrMuchimi
2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.

Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.

Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.

5 0
3 years ago
Which number is greater than 234,781,114?
posledela

Answer:

I think its B.

Step-by-step explanation:

sorry if i am wrong.

3 0
3 years ago
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