Using the fundamental counting theorem, we have that:
- 648 different area codes are possible with this rule.
- There are 6,480,000,000 possible 10-digit phone numbers.
- The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.
For the area code:
- 8 options for the first digit.
- 9 options for the second and third.
Thus:

648 different area codes are possible with this rule.
For the number of 10-digit phone numbers:
- 7 digits, each with 10 options.
- 648 different area codes.
Then

There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
A similar problem is given at brainly.com/question/24067651
Answer:
0
Step-by-step explanation:
the answer is 0
because it neither rises nor fall
Answer:
D
Step-by-step explanation:
A, B, and C are not linear functions
D would be y=x/2
If you graphed y=x/2, you would get the points (4, 2), (7, 3.5), (8, 4), and (10, 5)
It's more obvious if you notice that y is half of x.
If i were you, i would add one to 7x and fifteen. this gives you x^2+8x+16, a perfect square of x+4.