For the answer to the two questions above,
3x + 2y = 36.50 (I)
2x + 5y = 50 (II)
Eliminating x from the two equations by subtraction:
first we multiply equation I by 2 and equation II by 3
6x + 4y = 73
6x + 15y = 150
Subtracting the two,
-11y = -77
y = 7
He earns $7 at the coffee cart
Substituting y into equation I,
3x + 14 = 36.5
x = $7.50
So we can conclude that, he earns a greater wage of $7.50 at the library,
Its the first one because -3(-2)=6, 1(-2)=-2, 2(-2)=4 are all correct
Answer:
Step-by-step explanation:
Given a function 
, we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value "
" to another "
".
The rate of change of between and can be calculated as follows:
For:
Let's find 
and 
, where:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)
So:
And for:
Let's find and , where:
So:
<em>Translation:</em>
Dada una función , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor "" a otro "".
La tasa de variación de entre y , puede ser calculada de la siguiente forma:
Para:
Encontremos y , donde:
Entonces:
Y para:
Encontremos y , donde:
Entonces:
Answer:
=(2x-3y+4z)+(9x-8y+7z)
=2x+9x-3y-8y+4z+7z
=11x-11y+11z
hope like the answer
please mark the answer as brainliest
Answer: The plane is 6,547 feet from the closer edge of the runway.
This is a trigonometry problem that will involve setting up 2 different triangles. One going to the closer edge of the runway and the other going to the far end of the runway.
The constant between the 2 triangles is the height of the plane. You can solve for this is both triangles and set them equal to each other.
Do that will give you the equation:
x/tan(70) = (x+3000)/tan(76) where x is the distance to the closer end of the runway.
If you solve that equation, you will get x = 6547 feet.
