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3 years ago

Pls help

Mathematics

2 answers:

Korvikt [17]3 years ago

5 0

C is the answer to this question

Gala2k [10]3 years ago

3 0

Answer:

The correct option is C.

Step-by-step explanation:

From the given graph it is clear that the coordinates of the given point are (-1,4) , (0,4), (2,3) and (4,5).

Option B represent the same coordinate pairs.

It means at x=-1 the value of y is 4, at x=0 the value of y is 4, x=2 the value of y is 3, x=4 the value of y is 5.

According to the arrow diagram,

At x=-1 the value of y is 4, at x=0 the value of y is 6, x=3 the value of y is 5, x=4 the value of y is 5.

It is not same as the graph.

According to the table at x=-1 the value of y is 4, at x=0 the value of y is 4, x=2 the value of y is 3, x=4 the value of y is 5. It is same as the coordinates of the graph.

Only Arrows (with the numbers) representation does not show the same relation as the others.

Therefore the correct option is C.

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If x = false and y = false, is the statement: not x or not y a) true b) false

pantera1 [17]

Answer:

false

Step-by-step explanation:

X is equal to Y

therefore,

X = Y

X= false

Y = false

so,

false = false

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2 years ago

Solve the equation 4m = 28 for m. A. 3 B. 4 C. 5 D. 7

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D 28/4=7 that is the answer for the question

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3 years ago

Read 2 more answers

Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand

dybincka [34]

Answer: Part a) $P(a)=\frac{1}{\binom{r+w}{r}}$

part b) $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}$

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = $P(E)=\frac{Favourablecases}{TotalCases}$

For part a)

Probability that a red ball is drawn in first attempt = $P(E_{1})=\frac{r}{r+w}$

Probability that a red ball is drawn in second attempt= $P(E_{2})=\frac{r-1}{r+w-1}$

Probability that a red ball is drawn in third attempt = $P(E_{3})=\frac{r-2}{r+w-1}$

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = $P(E_{i})=\frac{r-i}{r+w-i}$

Thus the probability that events $E_{1},E_{2}....E_{i}$ occur in succession is

$P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...$

Thus $P(E)$ = $\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!$

Thus our probability becomes

$P(E)=\frac{1}{\binom{r+w}{r}}$

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at $(r+1)^{th}$ draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals $\binom{r}{r-1}$

Thus the probability becomes $P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}$

Thus required probability of case b becomes $P(E)+ P(E_{i})$

= $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\$

7 0

4 years ago

Guided Practice

SCORPION-xisa [38]

Answer:

$5352.90

Step-by-step explanation:

A=p(1+r)^t

A=4,000×(1+0.06)^(5)

A=5,352.90

.........................................................

Answer:

The Final Investment Value is

Step-by-step explanation:

we know that

The compound interest formula is equal to

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

substitute in the formula above

5 0

3 years ago

АA85°B11. GARDEN PATHS A circular garden has paths around its edge thatare identified by the given arc measures. It also has fou

ladessa [460]

⌒DE = 110°

⌒AC = 85° + 25° = 110°

Both arcs have the same measurement; so the chords are the same.

8 0

1 year ago