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stepan [7]
3 years ago
8

Pls help

Mathematics
2 answers:
Korvikt [17]3 years ago
5 0
C is the answer to this question

Gala2k [10]3 years ago
3 0

Answer:

The correct option is C.

Step-by-step explanation:

From the given graph it is clear that the coordinates of the given point are (-1,4) , (0,4), (2,3) and (4,5).

Option B represent the same coordinate pairs.

It means at x=-1 the value of y is 4, at x=0 the value of y is 4, x=2 the value of y is 3, x=4 the value of y is 5.

According to the arrow diagram,

At x=-1 the value of y is 4, at x=0 the value of y is 6, x=3 the value of y is 5, x=4 the value of y is 5.

It is not same as the graph.

According to the table at x=-1 the value of y is 4, at x=0 the value of y is 4, x=2 the value of y is 3, x=4 the value of y is 5. It is same as the coordinates of the graph.

Only Arrows (with the numbers) representation does not show the same relation as the others.

Therefore the correct option is C.

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3 years ago
An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

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A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

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y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
3 years ago
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slavikrds [6]

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look at the exponents, when dividing with exponents, you just subtract them, so it could also be 9^0, which is also 1

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