3 years ago

ANSWER ALL THREE I WILL MAKE YOU THE BRAINLIEST EASY QUESTION

Mathematics

2 answers:

Furkat [3]3 years ago

7 0

1-27/10
2-3 1/7
3- 3 5/6

Anna35 [415]3 years ago

4 0

Number 1 is 14/10 number 4 is 3 1/7 number 5 is 3 5/6

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Plz help me, URGENT!! 20 points!

Evgen [1.6K]

Answer:

The answer to your question is 37.5

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3 years ago

Help on this one. You will get 10 points

ad-work [718]

Answer:

A.true

Step-by-step explanation:

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2 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$