To obtain x, we can sum the angles < AQB and < BQC
=> 5X + 8X - 24
=> 13X -24
we are also told that that the sum of their angles is 80
13X - 24 = 80
13 X = 24 + 80
13X = 104
Divide both sides by 13
x = 104/13
x = 8
Answer:
see below
Step-by-step explanation:
sqrt(2)+ sqrt(98)
sqrt(2) + sqrt( 2*49)
sqrt(2) + 7sqrt(2)
8 sqrt(2)
oops answer is in the comments... there are two sides of the box that have a match. so take the area 60*60 and subtract ( 2*(30*40) + (30*5)*2 ) enough paper!!