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coldgirl [10]
3 years ago
12

A thumbtack that is tossed can land point up or point down. The probability of a tack landing point up is 0.2. A simulation was

conducted in which a trial consisted of tossing 5 thumbtacks and recording the number of thumbtacks that land point up. Many trials of the simulation were conducted and the results are shown in the histogram.
Based on the results of the simulation, which of the following is closest to the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed?

A 0.09

B 0.19

C 0.28

D 0.72

E 0.91

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
8 0

Answer:

Option C: 0.28

Step-by-step explanation:

This is a binomial probability distribution problem.

Now, we want to find the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed. This is written as;

P(X ≥ 2) = P(2) + P(3) + P(4) + P(5)

From the histogram;

P(5) = 0.02

P(4) = 0.02

P(3) = 0.05

P(2) = 0.19

Thus;

P(X ≥ 2) = 0.19 + 0.05 + 0.02 + 0.02

P(X ≥ 2) = 0.28

Delvig [45]3 years ago
7 0

Answer:

0.28

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given

See attachment

From the attachment, we have:

MN = 6

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First, we need to calculate length LM,

Using Pythagoras theorem:

LN^2 = MN^2 + LM^2

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Collect Like Terms

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Solving (a): \sin L

\sin L = \frac{Opposite}{Hypotenuse}

\sin L = \frac{MN}{LN}

Substitute values for MN and LN

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Solving (b): tan\ N

tan\ N = \frac{Opposite}{Adjacent}

tan\ N = \frac{LM}{MN}

Substitute values for LM and MN

tan\ N = \frac{8}{6}

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\cos L = \frac{Adjacent}{Hypotenuse}

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Substitute values for LN and LM

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\sin N = \frac{Opposite}{Hypotenuse}

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Substitute values for LM and LN

\sin N = \frac{8}{10}

\sin N = 0.80

7 0
3 years ago
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tatiyna

Answer:

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Step-by-step explanation:

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