The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
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Answer:
y=3x
Step-by-step explanation:
a) 8 -5v-3 = 5v-5
-5v+5 = 5v-5
identity
b) 3m-6 =4m+7
has 1 solution
c) 2w +4 = 5w -2w +4
2w+4 = 3w+4
w=0
one solution
d) 7y+9 = 7y-6
subtract 7y from each side
9=-6 impossible
no solution
Choice D
Answer:
We can now write this is a function of time in years leading to
f
(
x
)
=
200
(
.94
)
x
f
(
5
)
≈
147
Explanation:
Firs you should consider that if its exponential then it has some form similar to
3
x
. Where we have some known part (3) and the unknown part (
x
) that we are trying to find out. Mathematically we can say it has the form
a
x
. In this case we know what the
a
is and that is the entire population that was given to us. We know over time it will change but why are we even using the exponential model.
Well it turns out that if you multiply some value over and over again it has this form. Example we multiply
2
⋅
2
⋅
2
⋅
2
=
2
4
. So if something doubled over time then this is what would happen.
Now the problem is that it will continue to decrease at the same rate leading to
a
⋅
(
.94
)
because only
94
%
of the population remains each year. After two years
a
⋅
(
.94
)
⋅
(
.94
)
. We can now write this is a function of time in years leading to
f
(
x
)
=
200
⋅
(
.94
)
x
f
(
5
)
≈
147
Step-by-step explanation:
4x^2-5x-21 is of the form ax^2+bx+c, a quadratic equation.
so b in this case is -5
