|2x+4| > 8 breaks down into two inequalities: 2x+4 > 8 or 2x+4 < -8
Solving <span> 2x+4 > 8 leads to...
</span><span>2x+4 > 8
</span><span>2x+4-4 > 8-4
</span>2x > 4
2x/2 > 4/2
x > 2
Solving <span>2x+4 < -8 leads to...
</span><span>2x+4 < -8
</span><span>2x+4-4 < -8-4
</span>2x < -12
2x/2 < -12/2
x < -6
So either x > 2 or x < -6
You'll have 2 open circles at 2 and -6 on the number line. The shaded region will be the region to the left of -6 and to the right of 2. Basically everything but in between -6 and 2
Answer:
A =576 pi in ^2
Step-by-step explanation:
Circumference is given by
C = 2 * pi *r
48 pi = 2 * pi *r
divide by 2 pi
48 pi /2 pi = 2 * pi * r / 2 pi
24 = r
We can find the area by
A = pi r^2
A = pi (24)^2
A =576 pi in ^2
Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
3
Step-by-step explanation:
divide the top number by the bottom to always find the constant of proportionality :D
