For this question it is the difference of two perfect squares. This means your final answer will be (2x - 5)(2x + 5). This answer is not listed so it would be none of the above.
After review, B technically works because it is the difference of two perfect squares. This allows you to take the square root of each term while ignoring the sign and then place that back in with the original sign.
First find the length of the hypotenuse using pythagorean theorem
<span>c^2 = 5^2 + 7^2
c^2 = 25 + 49
c^2 = 64
c=8 (take the square root in both sides)
Since sin = opposite/hypotenuse,
sin = 5/8 = 0.625</span>
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
------>inequality A
The solution of the inequality A is the shaded area above the dashed line 
The y-intercept of the dashed line is (0,6)
The x-intercept of the dashed line is (-24,0)
The slope of the dashed line is positive m=1/4
------>inequality B
The solution of the inequality B is the shaded area above the dashed line 
The y-intercept of the dashed line is (0,-1)
The x-intercept of the dashed line is (0.5,0)
The slope of the dashed line is positive m=2
The solution of the system of inequalities is the shaded area between the two dashed lines
using a graphing tool
see the attached figure
Answer:
Any points on the line y=2/5 x - 6/5. See picture below.
Step-by-step explanation:
Convert the equation to slope intercept form and graph it.
2x - 5y = 6
-5y = 6 - 2x
y = -2/-5 x + 6/-5
y=2/5 x - 6/5.
Locate each of the points listed on the graph. If they are a part of the line, then they are solutions.
[Given]
{ x + y = 6
{ x = y + 4
[Plug-in our x value & solve]
[Given] x + y = 6
[ Plug-in] (y + 4) + y = 6
[Distribute] y + 4 + y = 6
[Combine like terms] 2y + 4 = 6
[Subtract 4 from both sides] 2y = 2
[Divide both sides by 2] y = 1
[Answer]
Third option - (5, 1)
-> You do not need to solve for x since this is the only option that has y = 1, but to solve for x we would do y + 4 = 1 + 4 = 5, so this answer fully checks correctly
Have a nice day!
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- Heather
