Answer:
13 m
Step-by-step explanation:
volume=1/2(b×h)×length/height
height =volume÷base area(1/2b×h)
832÷64=13m
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
Total value: $144
Explanation: each book cost $4.50
Answer:
Answer: 1/12
Step-by-step explanation:
2/5x-4=8-3/5x.
We want to tank x out of the denominator by multiplying x on both sides.
2/5-4x=8x-3/5
Now we simplify
-12x=-1
x=1/12
Put x in the equation to check it
9514 1404 393
Answer:
P(0) = 4
P(-2) = 2
Step-by-step explanation:
Put the value where the variable is and do the arithmetic.
P(0) = 2·0³ +3·0² -0 +4
P(0) = 4
__
P(-2) = 2·(-2)³ +3·(-2)² -(-2) +4 = 2(-8) +3(4) +2 +4
P(-2) = -16 +12 +2 +4
P(-2) = 2
