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ELEN [110]
3 years ago
13

HELP ME WITH MH GEOMETRY HW PLEASE

Mathematics
1 answer:
Elodia [21]3 years ago
7 0

Answer:

2a (blue)

2b (pink/purple)

3b (light blue)

4a (red)

4a (green)

6a (yellow)

2a (purple)

2a+2b (orange)

6a (pink)

4a-b (pinkk)

4a-2b (purple)

6a (green)

Step-by-step explanation:

2 right triangles (2a) make a square

4 right triangles (4a) make a rectangle

2 right triangles (2a) make a bigger triangle

This alone can help with most of them by combining these together and adding/removing semicircles.

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Let U = {3, 6, 9, 12, 15, 18, 21, 24} and A = {9, 12, 15, 21}. A'
miskamm [114]

Answer:

A¹ = { 3 , 6, 18 , 24}

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u>Universal set </u>

If all the sets under consideration are the subsets of a fixed set 'U' then the set 'U' is called the Universal set.

Given  U = {3, 6, 9, 12, 15, 18, 21, 24}

Given A = {9, 12, 15, 21}

<u><em>Compliment Of A</em></u>

The Complement of a set A is all the objects that do not belong to set A

The Compliment of A is denoted by A¹

A¹ = U - A

     = {3, 6, 9, 12, 15, 18, 21, 24} - {9, 12, 15, 21}

A¹ = { 3 , 6, 18 , 24}

4 0
3 years ago
The median and interquartile range of the a set of data is shown. Write a set of data consisting of seven values for the pair of
OleMash [197]
You use the definition of median and interquartile range. The def. of a median is the number in the middle of the data set, so the number 6 would be in the middle. Making a box and whisker plot(shown below) with the data set separates the data set into 4 "quartiles" or parts. The interquartile range is the last line in the box(Q3) minus the first line in the box(Q1). So something minus somthing must equal 5. 

Data set: 1,2,3,6,8,8,10
It doesn't matter what the other numbers are as long as the median is 6 and the interquartiel range is 6.

6 0
3 years ago
The two toy store owners agree to specialize and to trade 30 puzzles for 10 puppets. The terms of trade are still 3 puzzles for
likoan [24]

Based on the exchange rate, at the end of the trade, Lewis will have 31 puppets and 2 puzzles left over while Geppeto will have 158 puzzles and 4 puppets left over.

<h3>What is the exchange rate of puzzles for puppets?</h3>

The exchange rate of puzzles for puppets is 3 to 1.

Geppeto has 20 puppets to exchange for puzzles.

Lewis has 50 puzzles to exchange for puppets.

Number of times Lewis can exchange puzzles for puppets = 50/3 = 16 times.

Lewis will get 16 puppets in exchange for 48 puzzles.

Therefore;

Lewis will have 16 + 25 puppets = 31 puppets and 2 puzzles left over

Geppeto will have 48 + 100 puzzles = 158 puzzles and 4 puppets left over.

in conclusion, the exchange rate determines the how many puzzles and puppets will each one have after they complete their trade.

Learn more about exchange rate at: brainly.com/question/2202418

#SPJ1

7 0
2 years ago
Mason and Nora decided to swim across the river. Mason began swimming 1 minute earlier than Nora.
Mademuasel [1]
Mason:

time = t
V =  6 ft/s
Distance = v * t = 6t

Nora:

time = t - 60 [ I passed 1 minute to seconds]
V = 8 ft/s
Dsitance = v*t = 8 (t - 60)

Both distance are equal

6t = 8(t-60)
6t = 8t - 480
8t -6t = 480
2t = 480
t = 480/2
t = 240 s

Mason had been swimming for 240 seconds when both had swan the same distance.
5 0
4 years ago
Simplify exponential form
wolverine [178]

Answer:

( \frac{5}{4})^{6}

Step-by-step explanation:

\frac{4}{5}  \div  \bigg[  {\bigg( \frac{4}{5} \bigg)}^{7} .{\bigg( \frac{4}{5} \bigg)}^{0}\bigg]  \\  \\  =  \frac{4}{5}  \div  \bigg[  {\bigg( \frac{4}{5} \bigg)}^{7} .1\bigg] \\  \\  =  \frac{4}{5}  \div    {\bigg( \frac{4}{5} \bigg)}^{7}\\  \\  =  \frac{4}{5}  \times    {\bigg( \frac{5}{4}\bigg)}^{7} \\  \\  = {\bigg( \frac{5}{4}\bigg)}^{6}

5 0
3 years ago
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