Answer:
9x + 6
Step-by-step explanation:
<u>Step 1: Distribute</u>
5x + (x + 6) + 3x
5x + x + 6 + 3x
<u>Step 2: Combine like terms</u>
5x + x + 6 + 3x
9x + 6
Answer: 9x + 6
Answer:
(9,0)
Step-by-step explanation:
heyhey
Answer: choice B
Angle A = 63 degrees
side a = 13.4
side b = 6.8
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Given Info:
Angle C = 90 degrees
Angle B = 27 degrees
side c = 15
What is needed to be found:
Angle A, side a, side b
Finding side a
cos(angle) = adjacent/hypotenuse
cos(B) = BC/AB
cos(B) = a/15
cos(27) = a/15
15*cos(27) = a
13.3650978628256 = a
a = 13.3650978628256
a = 13.4
Finding side b
Using the pythagorean theorem
a^2 + b^2 = c^2
(13.3650978628256)^2 + b^2 = 15^2
178.625840882906 + b^2 = 225
178.625840882906 + b^2 - 178.625840882906 = 225 - 178.625840882906
b^2 = 46.374159117094
sqrt(b^2) = sqrt(46.374159117094)
b = 6.809857496093
b = 6.8
Finding angle A
sin(angle) = opposite/hypotenuse
sin(A) = BC/AB
sin(A) = a/c
sin(A) = 13.3650978628256/15
sin(A) = 0.89100652418838
arcsin(sin(A)) = arcsin(0.89100652418838)
A = 63.0000000000016
A = 63
Answer:
A = 0.75 gram or 1 gram
Step-by-step explanation:
The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole number).
We can use the following formula for half-life of 
to find out how much is left from the original sample after 2,292 years:
where:
<em>A</em> is the amount left of an original gram sample after <em>t</em> years, and
is the amount present at time <em>t</em> = 0.
The half-life of is the time <em>t</em> at which the amount present is one-half the amount at time <em>t </em>= 0.
If 1 gram of is present in a sample,
Solve for A when t = 2,292:
Substituting = 1 gram into the decay equation, and we have:
A = 0.75 g or 1 g
