9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Answer:
x= first number y= second
x=2y+9 and x+y=129, these are the equations...solving gives x=89,y=40
Step-by-step explanation:
Answer:
Step-by-step explanation:
Find the sum of the squares of the residuals for
y 2x 6
The first 6 is 600,00 and the second is 60,000, so they are in the hundred thousands place and the thousands place
Answer:
Step-by-step explanation:
If you draw a line from the origin (0,0) to L ( the original point ) and a different line from the origin to the image L' you can see the angle of rotation as being
90 degrees and that the rotation is clockwise.
the rule is (x, y) become ( y, -x)