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monitta
3 years ago
13

When algebraic, or numerical fractions are added or subtracted, the result is a single fraction. True False

Mathematics
1 answer:
Paul [167]3 years ago
7 0
I think that is true
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Which of the followint iw a linear equation
SpyIntel [72]

Answer:

11.C

12.B

Step by step explanation:

4 0
4 years ago
2/5x+1/5=-7/5<br> what is X ?
Artist 52 [7]
Hola !

The answer is = (-4) as in the attachment provided

Hope it helped you

8 0
3 years ago
A small square of side 2x is cut from the corner of a rectangle with a width of 10 centimeters and length of 20 centimeters. Wri
love history [14]
Find the area of the rectangle. You can find the area of a rectangle with the following formula:

A = wl

w = width, and l = length.

Plug in your width and length:

20 * 10 = 200

The area of the rectangle is 200 square centimeters.

The area of a square is also given by width * length. Multiply the sides together:

2x * 2x = 4x^{2}

The area of a square is 4x^2.

Because you're cutting away the square from the rectangle, you will subtract the area of the square from the area of the rectangle. The following equation will be your answer:

200 - 4x^{2} cm^{2}
6 0
3 years ago
Please help me, and please do not make a download, because I cannot download anything on my computer. THank you!!!
VikaD [51]

Answer:

(A)48

(B)volume of one of the small cubes is 1/64cm^3

c)3/4x1x1=3/4cm^3

Step-by-step explanation:

3 0
3 years ago
What are the intercepts of 2x + 3y – 6z = 30?
ycow [4]

Intercept of equation 2x + 3y - 6z = 30 is (15, 0, 0) , (0, 10, 0) and (0, 0, -5)

<h3><u>Solution:</u></h3>

Given equation is:

2x + 3y - 6z = 30

We have to find the intercepts

Intercept are the point where equations cut the x- axis, y- axis and z- axis.

<em><u>Thus, at x- axis :</u></em>

y and z both are zero

So substitute y = 0 and z = 0 in given equation

2x + 3(0) - 6(0) = 30

2x = 30

x = 15

<h3>Thus the intercept is (15, 0, 0)</h3>

<em><u>Thus at y - axis:</u></em>

x and z both are zero

So substitute x = 0 and z = 0 in given equation

2(0) + 3y -6(0) = 30

0 + 3y + 0 = 30

3y = 30

y = 10

<h3>Thus the intercept is (0, 10, 0)</h3>

<em><u>Thus at z - axis:</u></em>

x and y are both zero

So substitute x = 0 and y = 0 in given equation

2(0) + 3(0) - 6z = 30

-6z = 30

z = -5

<h3>Thus the intercept is (0, 0, -5)</h3>

Thus, intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

6 0
3 years ago
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