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kotykmax [81]
3 years ago
13

Kyle had a balance of -5 dollars in his checking account. After he deposits a certain amount of money into the account, the bala

nce is now 15 dollars.
How much money did Kyle deposit into his checking account?
Mathematics
1 answer:
aleksley [76]3 years ago
4 0

Answer:

$20

Step-by-step explanation:

start with an equation. 15-(-5)=x. double negatives make positive so it becomes 15+5=x. therefore 20=x (x being the number kyle deposited).

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Answer:

  • B. -23

Step-by-step explanation:

<u>I assume it is:</u>

  • |5| - 4(3² - 2)

<u>Simplifying in steps:</u>

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  • 5 - 28 =
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Correct choice is B

7 0
2 years ago
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3 years ago
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The system of equations below has no solution.
mixer [17]

Answer:

  • Second option: 0 = 26

Explanation:

This is the given system of equations:

\frac{2}{3} x+\frac{5}{2} y=15\\ \\ 4x+15y=12

A linear combination of the system is any equation formed by the algebraic addition of both equations, one or both multiplied by an arbitrary constant.

To prove that the given system has no solution you could multiply the first equation times 6 (to get rid of the fractions), multiply the second equation times - 1, and add the two results:

<u>1. First equation times 6:</u>

6\times\frac{2}{3} x+6\times\frac{5}{2}y=6\times 15\\ \\ 4x+15y=90

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<u>2. Second equation times - 1:</u>

-4x-15y=-12

<u />

<u>3. Add the two new equations:</u>

0=78

<u />

<u>4. Conclusion:</u>

Since 0 = 78 is false, no matter what the value of x and y are, the conclusion is that the system of equations has not solution.

The only choice that represents that same situation is the second one, 0 = 26. That is a possible linear combination that represents that the system of equations has no solutions.

In fact, you might calculate the exact factors by which you had to multiply each one of the original equations to get 0 = 26, but it is not necessary to tell that that option represents a possible linear combination for the given system of equations.

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3 years ago
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A student earned a grade 80% on a math test that had 20 problems. How many problems on this test did the student answer correctl
prohojiy [21]

Answer:

16

Step-by-step explanation:

5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80

8 0
3 years ago
You have 250,000 In an IRA at the time you retire.You have the option of investing this money in two funds.Fund A pays 1.2% annu
krok68 [10]

Let x be the amount of money, you fund in Fund A and y be the amount of mone yyou fund in Fund B.

1. You have 250,000 In an IRA at the time you retire and want to invest this money into Funds A and B, then

x+y=250,000.

2. Fund A pays 1.2% (as a decimal 1.2% is 0.012) annually, then x\cdot 0.012=0.012x is annual interest income in Fund A.

Fund B pays 6.2% (as a decimal 6.2% is 0.062) annually, then y\cdot 0.062=0.062y is annual interest income in Fund B.

Since Fund A and Fund B produce an annual interest income of $8,000, then

0.012x+0.062y=8,000.

3. Solve the system of equations:

\left\{\begin{array}{l}x+y=250,000\\0.012x+0.062y=8,000.\end{array}\right.

Express x from first equation x=250,000-y and substitute it into the second equation

0.012(250,000-y)+0.062y=8,000.

Multiply this equation by 1000:

12(250,000-y)+62y=8000,000,\\ \\3000,000-12y+62y=8000,000,\\ \\62y-12y=8000,000-3000,000,\\ \\50y=5000,000,\\ \\y=100,000

Then

x=250,000-100,000=150,000.

Answer: you have to fund $150,000 in Fund A and $100,000 in Fund B.


8 0
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