All categories

2 years ago

How to use the distrubtive property to multiply a number by a sum

Mathematics

1 answer:

gavmur [86]2 years ago

8 0

The distributive property of multiplication over addition is used when we multiply a number by a sum.

For example:

Lets suppose we want to multiply 7 by the sum of (15+3). So, according to this property, we can add the numbers and then multiply by 7.

It can be written like this :

$7(15+3)$

$7(18)$

= 126

You might be interested in

Find the experimental probability Roll dice 1,3,3,4,4 P(1)= I’ll give brainleist

-Dominant- [34]

Answer:

$\mathrm{P(1)\:}=\frac{1}{5}$

Step-by-step explanation:

There are simply 5 possible values in the given set. Out of these, only one of these is the number 1. Therefore, the probability a 1 is drawn (P(1)) is $\fbox{$\frac{1}{5}$}$ .

5 0

2 years ago

Read 2 more answers

What is the simplified version of 10x(426)

Effectus [21]

4260 is the answer

i dont know what you mean by simplified

3 0

3 years ago

Read 2 more answers

True or false: A triangle can be made by segments that are 15.9 cm, 10 cm and 25.9 cm.

Gala2k [10]

Answer:

false

Step-by-step explanation:25.9cm is too big to connect to 15.9cm and 10 cm

4 0

1 year ago

The length of a rectangle is 1.2 × 10-4 kilometer. the width of the rectangle is 6.25 × 10-5 kilometer.what is the area in squar

Serhud [2]

We have 1.2 × 10^(-4) x 6.25 × 10^(-5 ) = 7,5 x 10^(-9) = 75 x 10^(-10) square kilometers.

3 0

2 years ago

Please show me step by step how to do this

Stels [109]

Answer:

The next three terms of the sequence are 17, 21 and 25.

The 300th term of the sequence is 1197.

Step-by-step explanation:

The statement describes an arithmetic progression, which is defined by following formula:

$p(n) = p_{1}+r\cdot (n-1)$ (1)

Where:

$p_{1}$ - First element of the sequence.

$r$ - Progression rate.

$n$ - Index of the n-th element of the sequence.

$p(n)$ - n-th element of the series.

If we know that $p_{1} = 1$ , $n = 2$ and $p(n) = 5$ , then the progression rate is:

$r = \frac{p(n)-p_{1}}{n-1}$

$r = 4$

The set of elements of the series are described by $p(n) = 1 + 4\cdot (n-1)$ .

Lastly, if we know that $n = 300$ , then the 300th term of the sequence is:

$p(n) = 1 + 4\cdot (n-1)$

$p(n) = 1197$

And the next three terms of the sequence are:

n = 5

$p(n) = 1 + 4\cdot (n-1)$

$p(n) = 17$

n = 6

$p(n) = 1 + 4\cdot (n-1)$

$p(n) = 21$

n = 7

$p(n) = 1 + 4\cdot (n-1)$

$p(n) = 25$

The next three terms of the sequence are 17, 21 and 25.

The 300th term of the sequence is 1197.

8 0

2 years ago