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goldenfox [79]
3 years ago
12

Which of the following is not a fee that contributes to the initial cost of leasing a car?

Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0

Answer:

B. Final Payment

A. Principal Charge

Step-by-step explanation:

Harlamova29_29 [7]3 years ago
3 0
Here are the answers to the questions above:
1. Based on the list of fees above, the one that does not contribute to the <span>initial cost of leasing a car is the FINAL PAYMENT. Answer would be option B.
2. In leasing a car, the amount that does not affect the total cost is the PRINCIPAL CHARGE, and the answer for this is option A. 
Hope this helps.</span>
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The diagram shows a dilation. Which dilation does it represent? <br> What is the scale factor?
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Answer:

which dilation does it represent?:

enlargement

which is the scale factor?:

2

Step-by-step explanation:

i did the assignment and got it correct

5 0
2 years ago
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7.5g of sugar is needed for every cake made how much sugar is needed for 10 cakes
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75 g

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3 years ago
If you graphed the equation, y = -6, what kind of line would you create?
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2 years ago
Find the values of sin2u, cos2u, and tan2u given the figure.
Vadim26 [7]

Givens

y = 2

x = 1

z(the hypotenuse) = √(2^2 + 1^2)  = √5

Cos(u) = x value / hypotenuse = 1/√5

Sin(u) = y value / hypotenuse = 2/√5

Solve for sin2u

Sin(2u) = 2*sin(u)*cos(u)

Sin(2u) = 2(\dfrac{1}{\dsqrt{5}} * \frac{2}{\dsqrt{5}} = \dfrac{2}{5}) = 4/5

Solve for cos(2u)

cos(2u) = - sqrt(1 - sin^2(2u))

Cos(2u) = - sqrt(1 - (4/5)^2 )

Cos(2u) = -sqrt(1 - 16/25)

cos(2u) = -sqrt(9/25)

cos(2u) = -3/5

Solve for Tan(2u)

tan(2u) = sin(2u) / cos(2u) = 4/5// - 3/5 = - 0.8/0.6 = - 1.3333 = - 4/3

Notes

One: Notice that you would normally rationalize the denominator, but you don't have to in this case.  The formulas are such that they perform the rationalizations themselves.

Two: Notice the sign on the cos(2u). The sin is plus even though the angle (2u) is in the second quadrant. The cos is different. It is about 126 degrees which would make it a negative root (9/25)

Three: If you are uncomfortable with the  tan, you could do fractions.

\text{tan(2u)} = \dfrac{\dfrac{4}{5}}{\dfrac{-3}{5} } =\dfrac{4}{5} *\dfrac{5}{-3} =\dfrac{4}{-3}

7 0
3 years ago
In practice, the most frequently encountered hypothesis test about a population variance is a _____. a. two-tailed test, with eq
Bas_tet [7]

Answer:

c. one-tailed test, with rejection region in the upper tail.

Step-by-step explanation:

One tailed test is statistical test in which critical area of distribution is one sided and greater or less than certain value. One tailed test can be left or right sided depending on the population distribution. Rejection region of the one tailed test will determine whether to accept or reject the null hypothesis.

8 0
3 years ago
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