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padilas [110]
3 years ago
7

A 180 ft long board is cut into 3 pieces. The second piece of board is twice as long as the first. The third piece of board is s

ix times as long as the first.
What is the length of the first piece of the board?
A. 20 ft
B. 40 ft
C. 60 ft
D. 120 ft
Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

Step-by-step explanation:

let  the first piece=x ft

second piece=2 x ft.

third piece=6 x ft.

x+2x+6x=180

9 x=180

x=20

first piece=20 ft.

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wolverine [178]

Answer: The confidence interval will be -91.87 < μ₁-μ₂ <751.87

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is the interval of certainty in which the true population mean is in.

In a confidence interval for the difference between two averages with a sample size less than 30, the calculations are:

x_{1}-x_{2} ± t.S_{p}\sqrt{\frac{1}{n_{1}} +\frac{1}{n_{2}} }

in which

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S_{p} is the pooled estimate of the common standard deviation, assuming variances are similar, and can be calculated as:

S_{p}=\sqrt{\frac{(n_{1}-1)(s_{1})^{2}+(n_{2}-1)(s_{2})^{2}}{n_{1}+n_{2}-2} }

n₁ and n₂ are sample sizes

The data to construct the interval are:

Mine A:

x₁ = 8260

s₁ = 251.9

n₁ = 5

Mine B:

x₂ = 7930

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S_{p}=\sqrt{\frac{(5-1)(251.9)^{2}+(5-1)(206.52)^{2}}{8}

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Using a table, for a 99% confidence and df = 8, t-score = 2.896.

Doing calculations:

(8260-7930) ± (2.896)(230.33)(\sqrt{\frac{1}{5} +\frac{1}{5} })

330 ± (2.896)(230.33)(\sqrt{0.4})

330 ± 421.87

Interval will be

-91.87

A 99% confidence interval for the difference between the true average heat-producing capacities of coal from the mines is between -91.87 and 751.87

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