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svet-max [94.6K]
3 years ago
7

A number is multiplied by 3. If 3 is subtracted from the product you get 24. What is the number?

Mathematics
1 answer:
ZanzabumX [31]3 years ago
3 0
The answer is 9
24+3=27
27/3=9
:) Hope this helps!

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There are 24 boys and 16 girls on the playground. What is the ratio of boys to total number of children on the playground?​
Reil [10]

Answer:

6 to 4

Step-by-step explanation:

24/4 = 6 Boys

16/4 = 4 Girls

Boys 6 / Girls 4

5 0
2 years ago
Let g(x)=9x−10 and evaluate g(x+h)−g(x)/h
castortr0y [4]

Answer:

\frac{g(x+h)-g(x)}{h}=9

Step-by-step explanation:

we have

g(x)=9x-10

To find out g(x+h) substitute the variable x by the variable (x+h) in the function g(x)

so

g(x+h)=9(x+h)-10

g(x+h)=9x+9h-10

Evaluate

\frac{g(x+h)-g(x)}{h}

we have

g(x+h)=9x+9h-10

g(x)=9x-10

substitute in the expression

\frac{9x+9h-10-(9x-10)}{h}

\frac{9x+9h-10-9x+10)}{h}

\frac{9h}{h}

9

therefore

\frac{g(x+h)-g(x)}{h}=9

3 0
3 years ago
Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. What perce
LenKa [72]

Answer:

14.28% of individual adult females have weights between 75 kg and 83 ​kg.

92.82% of the sample means are between 75 kg and 83 ​kg.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. This means that \mu = 79, \sigma = 22.

What percentage of individual adult females have weights between 75 kg and 83 ​kg?

This percentage is the pvalue of Z when X = 83 subtracted by the pvalue of Z when X = 75. So:

X = 83

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 79}{22}

Z = 0.18

Z = 0.18 has a pvalue of 0.5714.

X = 75

Z = \frac{X - \mu}{\sigma}

Z = \frac{75- 79}{22}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286.

This means that 0.5714-0.4286 = 0.1428 = 14.28% of individual adult females have weights between 75 kg and 83 ​kg.

If samples of 100 adult females are randomly selected and the mean weight is computed for each​ sample, what percentage of the sample means are between 75 kg and 83 ​kg?

Now we use the Central Limit THeorem, when n = 100. So s = \frac{22}{\sqrt{100}} = 2.2.

X = 83

Z = \frac{X - \mu}{s}

Z = \frac{83 - 79}{2.2}

Z = 1.8

Z = 1.8 has a pvalue of 0.9641.

X = 75

Z = \frac{X - \mu}{s}

Z = \frac{75-79}{2.2}

Z = -1.8

Z = -1.8 has a pvalue of 0.0359.

This means that 0.9641-0.0359 = 0.9282 = 92.82% of the sample means are between 75 kg and 83 ​kg.

8 0
3 years ago
Identify the percent of change from 2/5 to 1/3 as an increase or a decrease.
Harrizon [31]

Answer:

V1 2 and V2 1

Step-by-step explanation:

look at the picture above to get ur answer

5 0
3 years ago
The table shows ordered peirs of the function y= 8 - 2x what is the value of y when x = 8
LuckyWell [14K]

Answer:

y = -8

Step-by-step explanation:

All we need to is substitute for x and solve for y.

y = 8 - 2x

y = 8 - 2(8)

y = 8 - 16

y = -8

Best of Luck!

3 0
3 years ago
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