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Sloan [31]
3 years ago
15

18. A science teacher has a supply of 20% saline solution and a supply of 50% saline solution. How much of each solution should

the teacher mix together to get 60 mL of 28% saline solution for an experiment? (1 point) A) 16 mL of the 20% solution and 44 mL of the 50% solution B) 44 mL of the 20% solution and 16 mL of the 50% solution C) 16 mL of the 20% solution and 16 mL of the 50% solution D) 44 mL of the 20% solution and 44 mL of the 50% solution
I know the answer is b but could someone explain how to get that answer
Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0
<span>44 mL of the 20% solution and 16 mL of the 50% solution  is your answer


</span>
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antoniya [11.8K]

Answer:

2 1/25  or 2.04

Step-by-step explanation:

8 ^ 1/3 + 5 ^ (-2)

Rewriting

(2^3) ^ 1/3 + 1/5 ^2

2 + 1/25

2 1/25

2.04

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In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

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So, triangles CBH and BCK are congruent by ASA postulate.

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BH ≅ CK.

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Answer:

Step-by-step explanation:

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