Alright so if I do remember my math correctly, this is how it goes:
- y = -x^2 + x + 3
- x = -b/2a
- x = -1/2(-1)
- x = -1/-2, which = (1/2)
Not quite sure if this was correct, but if it was, hope this helps and you're welcome! :)
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer:
Step-by-step explanation:
Jada is making circular invitations
we have d=12 cm, the radius r=6
she needs to find out the circumference
C=2x3.14x r
C=2x 3.14x6=37.68
180/37.68=4.77
she can make just 4 invitations
That would be 1/2 divided by 3
Its A
