Answer:
refer this picture
Step-by-step explanation:
hope it helps you.It is used for maths while you are writing this standard form.
Hope it helps you.
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Answer:
3(5 +6) = <em>33</em>
Step-by-step explanation:
3(5+6)
so first you multiply 3 by 5
which is 15
then you multiply 3 by 6
which is 18
and that remains as 15+18
which in total equals <em>33</em>
Answer:
![r=\sqrt{\dfrac{75}{\pi}}\approx 4.89\ in](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%5Cdfrac%7B75%7D%7B%5Cpi%7D%7D%5Capprox%204.89%5C%20in)
Step-by-step explanation:
If the water in the cube rose from 6 inches to 8 inches when the cone was placed in the cube, then the difference in volumes is the volume of the submerged portion of the cone.
Initially, 10 in by 10 in by 6 in:
![V_{initial}=10\cdot 10\cdot 6=600\ in^2.](https://tex.z-dn.net/?f=V_%7Binitial%7D%3D10%5Ccdot%2010%5Ccdot%206%3D600%5C%20in%5E2.)
At he end, 10 in by 10 in by 8 in:
![V_{final}=10\cdot 10\cdot 8=800\ in^3.](https://tex.z-dn.net/?f=V_%7Bfinal%7D%3D10%5Ccdot%2010%5Ccdot%208%3D800%5C%20in%5E3.)
Thus,
![V_{submerged \ cone}=800-600=200\ in^3.](https://tex.z-dn.net/?f=V_%7Bsubmerged%20%5C%20cone%7D%3D800-600%3D200%5C%20in%5E3.)
Use cone's volume formula
![V_{cone}=\dfrac{1}{3}\pi r^2 \cdot h,](https://tex.z-dn.net/?f=V_%7Bcone%7D%3D%5Cdfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2%20%5Ccdot%20h%2C)
where r is the radius of the cone's base, h is the height of the cone.
From the diagram, h=8 in, then
![200=\dfrac{1}{3}\cdot \pi\cdot r^2\cdot 8\\ \\\pi r^2=75\\ \\r^2=\dfrac{75}{\pi}\\ \\r=\sqrt{\dfrac{75}{\pi}}\approx 4.89\ in](https://tex.z-dn.net/?f=200%3D%5Cdfrac%7B1%7D%7B3%7D%5Ccdot%20%5Cpi%5Ccdot%20r%5E2%5Ccdot%208%5C%5C%20%5C%5C%5Cpi%20r%5E2%3D75%5C%5C%20%5C%5Cr%5E2%3D%5Cdfrac%7B75%7D%7B%5Cpi%7D%5C%5C%20%5C%5Cr%3D%5Csqrt%7B%5Cdfrac%7B75%7D%7B%5Cpi%7D%7D%5Capprox%204.89%5C%20in)
4x +5x +6x = 180
15x = 180
x = 180/15
x = 12
So smallest angle = 4*12 = 48 degrees
3.5 tons because 1 ton is 2000 pounds