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GenaCL600 [577]
3 years ago
10

one gym chargers $40 per month and $3 per exercise class. another gym charges $20 per month and $8 per exercise class. after how

many exercise classes will the monthly cost be the same and what will that cost be?
Mathematics
1 answer:
S_A_V [24]3 years ago
7 0
4 classes, $52
Do it the long way to check
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Solve quadratic equations by factoring<br> x cubed +3x squared - 4x= 0
Papessa [141]
<span>x cubed +3x squared - 4x= 0
= x^3 + 3x^2 -4x = 0
=x(x^2 +3x -4) = 0
= x (x+4)(x-1) = 0

x = 0
x+ 4 = 0 then x = -4
x - 1 = 0 then x = 1
answer: x = 0, x = -4 and x = 1</span>
8 0
3 years ago
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The tires of a tractor are 4.5 feet tall. How many 360-degree rotations do the tires make when the tractor travels 170 feet? Rou
Arturiano [62]

Answer:

170÷(4.5×2×3.14)=170÷28.26=6

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3 years ago
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Of the population of all fruit flies we wish to give a 90% confidence interval for the fraction which possess a gene which gives
maks197457 [2]

Answer:

The margin of error for the 90% confidence interval is of 0.038.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

To this end we have obtained a random sample of 400 fruit flies. We find that 280 of the flies in the sample possess the gene.

This means that n = 400, \pi = \frac{280}{400} = 0.7

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

Give the margin of error for the 90% confidence interval.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.645\sqrt{\frac{0.7*0.3}{400}}

M = 0.038

The margin of error for the 90% confidence interval is of 0.038.

8 0
3 years ago
Find the exact value of the following limit: lim x approaches 0 e^6x... check photo above.​
horrorfan [7]

Substituting <em>x</em> = 0 directly gives the indeterminate form 0/0, so you can use l'Hopital's rule (and you'll have to do that twice):

\displaystyle\lim_{x\to0}\frac{e^{6x}-6x-1}{x^2}=\lim_{x\to0}\frac{6e^{6x}-6}{2x}=\lim_{x\to0}\frac{36e^{6x}}2

The limand is continuous everywhere, so you can plug in <em>x</em> = 0 to get 36•1/2 = 18.

8 0
3 years ago
Alyson worked at a clothing store for the summer. She started in June and her pay increased by 10% each month. Alyson earned $2,
g100num [7]

Answer:

i THINK anyson earned 1742.4 a month in June but I’m a middle schooler so

Step-by-step explanation:

The internet

4 0
2 years ago
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