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antoniya [11.8K]
3 years ago
11

Find the exact value of the following limit: lim x approaches 0 e^6x... check photo above.​

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Substituting <em>x</em> = 0 directly gives the indeterminate form 0/0, so you can use l'Hopital's rule (and you'll have to do that twice):

\displaystyle\lim_{x\to0}\frac{e^{6x}-6x-1}{x^2}=\lim_{x\to0}\frac{6e^{6x}-6}{2x}=\lim_{x\to0}\frac{36e^{6x}}2

The limand is continuous everywhere, so you can plug in <em>x</em> = 0 to get 36•1/2 = 18.

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