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3 years ago

Generate two equivalent fractions for 1/3

1 answer:

7 0

If you have a fraction, you can multiply any constant, if you do it on both the top and bottom and get the same answer. For example, multiply 2 on both sides of 1/3 to get 2/6, or 3 times 1/3 to get 3/9. So 2/6 or 3/9 would work.

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Help please need to be done now

4vir4ik [10]

The radius of the new sphere is 9

The new SA should be 1017.36 in

New volume should be 3052.08in^3

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3 years ago

Dylan and Spencer went looking for Dylan's lost dog. Dylan traveled 100 meters to the neighbor’s house, 1.5 kilometers to the pe

scZoUnD [109]

Answer: 641

Step-by-step explanation:

100m + 310m= 410m + 1.5km=1910

1910 - 1269= 641

4 0

4 years ago

Read 2 more answers

At a recent KCMS dance, students were surveyed to find that there were 45 lower school students and 70 upper school students.Wha

Mrac [35]

First you add 45+70=115, next you put 70 over 115 so it’s a fraction. Divide 70 by 115 which is about 0.6086, finally, you move the decimal two spots to the right. The answer is 60.86%

6 0

3 years ago

If y varies directly with x and y=10 when x=5, what is the value of k?

disa [49]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we know that }
\begin{cases}
y=10\\
x=5
\end{cases}\quad 10=k5\implies \cfrac{10}{5}=k\implies 2=k$

8 0

4 years ago

Read 2 more answers

What is the domain of the function <br> y=3√6x+42 A. x ≥ 0<br> B. x ≤ 7<br> C. x ≥ –6<br> D. x ≥ –7

soldi70 [24.7K]

Answer: The correct option is (D) $x\geq -7.$

Step-by-step explanation: We are given to find the domain of the following function:

$y=3\sqrt{6x+42}~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

The domain of a function y = f(x) is the set of all possible x-values which will make the function defined or will output real y-values.

That is, for the function (i), the domain will be given by all those values of x for which $3\sqrt{6x+42}$ is real.

Now, the values of y will be real only if the expression under square root is greater than or equal to 0.

Therefore, the domain of function (i) is

$\sqrt{6x+42}\geq0\\\\\Rightarrow 6x+42\geq 0\\\\\Rightarrow 6x\geq -42\\\\\Rightarrow x\geq -\dfrac{42}{6}\\\\\Rightarrow x\geq -7.$

Thus, the domain of the given function is $x\geq -7.$

Option (D) is CORRECT.

7 0

4 years ago

Read 2 more answers