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3 years ago

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Alice bought a 2-foot sub sandwich.The sandwich was cut into 10 pieces. Beth ate 1/5 of the sandwich , Camila ate 3/10 of the sa

ndwich, and Alice ate two pieces
How many pieces of the sandwich did the 3 girls eat altogether? Enter your answer in the box

1 answer:

Sholpan [36]3 years ago

5 0

Answer:

5/10 or 1/2

Step-by-step explanation:

Beth ate 2/10 so 2/10+3/10+2/10=5/10=1/2

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On Monday, Florencia's hair was h centimeters long. She got a haircut on Tuesday, so her hair was only 75%, percent of the lengt

irga5000 [103]

It seems that you are trying to find the length of hair of Florencia on Tuesday.

Given that length of the hair of Florencia on Monday = h centimeters

On Tuesday, she got hair cut.

So new length of the hair of Florencia on Tuesday = 75% of Monday value

= 75% of (h)

= 0.75* (h)

= 0.75h

Hence final answer is the length of the hair of Florencia on Tuesday is ( 0.75h ) centimeters.

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Uninhibited growth can be modeled by exponential functions other than A(t) =Upper A 0 e Superscript kt. For example, if an i

laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than $A(t)=A_{0}e^{kt}$ . for example, if an initial population P₀ requires n units of time to triple, then the function $P(t)=P_{0}(3)^{\frac{t}{n} }$ models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form $P(t)=P_{0}(3)^{\frac{t}{n} }$ that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form $A(t)=A_{0}e^{kt}$ .

Answer: a) $P(t)=50(3)^{\frac{t}{30} }$

b) P(t) = 280 insects

c) t = 74 days

d) $A(t)=50e^{0.037t}$

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

$P(t)=50(3)^{\frac{t}{30} }$

b) In t = 47 days:

$P(t)=50(3)^{\frac{t}{30} }$

$P(47)=50(3)^{\frac{47}{30} }$

$P(47)=50(3)^{1.567}$

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

$750=50(3)^{\frac{t}{30} }$

$\frac{750}{50}=(3)^{\frac{t}{30} }$

$(3)^{\frac{t}{n} }=15$

Using the property <u>Power</u> <u>Rule</u> of logarithm:

$log(3)^{\frac{t}{30} }=log15$

$\frac{t}{30}log(3)=log15$

$t=\frac{log15}{log3} .30$

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

$A(t)=A_{0}e^{kt}$

$3A_{0}=A_{0}e^{30k}$

$3=e^{30k}$

Use Power Rule again:

$ln3=ln(e^{30k})$

$ln3=30k$

$k=\frac{ln3}{30}$

k = 0.037

Equation for exponential growth will be:

$A(t)=50e^{0.037t}$

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MrRissso [65]

Answer:

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Answer:

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How many terms are in the expression 36x^3+27x^2-18x-9

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Answer:

Four (4) terms.

Step-by-step explanation:

36x³ + 27x² - $18x^{1}$ - $9x^{0}$

The gives four terms.

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