LN = 120 and a = 10
<u>Step-by-step explanation:</u>
If we need to find the variable a as, LN is the line and M is the mid point between L and N. So LN = LM + MN
LM = 4a = 40
a = 
= 10
MN = 8a = 8×10 = 80
So LN = LM + MN
LN = 40 + 80 = 120
<span>Volume of a square = (s)(s)(s) and s=5a+4b
Therefore: (5a+4b)(5a+4b)(5a+4b)=
(25a^2+40ab+16b^2)(5a+4b)=
(125a^3+200a^2b+80ab^2+100a^2b+160ab^2+64b^3)= (125a^3+300a^2b+240ab^2+64b^3)
You just multiple the first time the second and then do so again with the combination of the first two times the second. A little cleaning up and you are left with an equation in terms of a and b.</span>
The correct answer is: [A]: " -60 " .
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Explanation:
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We are asked to find the "product" of the two numbers, " 12 " and " -5 " .
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The "product" refers to the result of "multiplying" numbers.
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So, what is the value, when "12" is multiplied by "-5" ?
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<u>Note</u>: When a "positive number" is multiplied by a "negative number" , the result is a "negative number" .
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So; the product of "12" and "-15" is: " 12 * -5 " ; which equals: " -60 " ;
which is: Answer choice: [A]: " - 60 " .
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Answer:
12/5
Step-by-step explanation:
6(2/5)
= (6/1) * (2/5)
= (6)(2) / (1)(5)
= 12/5
We want to solve the Initial Value Problem y' = y + 4xy, with y(0) = 1.
To use Euler's method, define
y(i+1) = y(i) + hy'(i), for i=0,1,2, ...,
where
h = 0.1, the step size.,
x(i) = i*h
1st step.
y(0) = 1 (given) and x(0) = 0.
y(1) ≡ y(0.1) = y(0) + h*[4*x(0)*y(0)] = 1
2nd step.
x(1) = 0.1
y(2) ≡ y(0.2) = y(1) + h*[4*x(1)*y(1)] = 1 + 0.1*(4*0.1*1) = 1.04
3rd step.
x(2) = 0.2
y(3) ≡ y(0.3) = y(2) + h*[4*x(2)*y(2)] = 1.04 + 0.1*(4*0.2*1.04) = 1.1232
4th step.
x(3) = 0.3
y(4) ≡ y(0.4) = y(3) + h*[4*x(3)*y(3)] = 1.1232 + 0.1*(4*0.3*1.1232) = 1.258
5th step.
x(4) = 0.4
y(5) ≡ y(0.5) = y(4) + h*[4*x(4)*y(4)] = 1.258 + 0.1*(4*0.4*1.258) = 1.4593
Answer: y(0.5) = 1.4593
