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soldi70 [24.7K]
3 years ago
12

What display can be used to find how many pumpkins had masses below 6.0 kilograms. Histogram or box plot

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0

Answer:

The correct option is Histogram.

Step-by-step explanation:

In statistics, we usually come across a vast set of data. Data can be explained well when it is presented as a graph rather than as a table since the graphs have the capability to make known a trend or comparison.  

Different types of graphs used in statistics to describe data are:

  • Bar charts
  • Pie charts
  • Line charts
  • Histogram
  • Box Plot
  • Dot Plot

And so on.

The methods commonly used for depicting a frequency distribution are:

  • Histogram/Column graph
  • Bar graph
  • Frequency Polygon
  • Pie chart

A histogram is used to graphically represent the distribution of a random variable according to the frequency distribution.

Each bar of the histogram is constructed according to a range of values and represents the frequency for that particular range.

In this case, we need to find  how many pumpkins had masses below 6.0 kilograms.

The histogram can be used to construct the graphically representation of the masses of pumpkins and their frequency.

The range can be decided according to the provided masses.

Thus, the correct option is Histogram.

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iogann1982 [59]
<h2>Hello!</h2>

The answer is:

The maximum height before landing will be 69.7804 feet.

<h2>Why?</h2>

Since there is no information about the angle of the launch, we can safely assume that it's launched vertically.

So, we can calculate the maximum height of the pumpkin using the following formulas:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

v=vo-gt

Where,

y, is the final height

y_o, is the initial height

g, is the acceleration of gravity , and it's equal to:

g=32.2\frac{ft}{s^{2} }

t, is the time.

Now, we are given the following information:

y_{o}=12ft\\\\v=61\frac{ft}{s}

Then, to calculate the maximum height, we must remember that at the maximum height, the speed tends to 0, so, calculating we have:

Time calculation,

We need to use the following equation,

v=vo-gt

So, substituting we have:

v=61\frac{ft}{s}-32.2\frac{ft}{s^{2}}*t\\\\-61\frac{ft}{s}=-32.2\frac{ft}{s^{2}}*t\\\\t=\frac{-61{ft}{s}}{-32.2\frac{ft}{s^{2}}}=1.8944s

We know that it will take 1.8944 seconds to the pumpkin to reach its maximum height.

Maximum height calculation,

Now, calculating the maximum height, we need to use the following equation:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

Substituting and calculating, we have:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}\\\\y_{max}=12ft+115.5584ft-16.1\frac{ft}{s^{2}}*(3.5887s^{2})\\\\y_{max}=127.5584ft-57.7780ft=69.7804ft

Hence, we have that the maximum height before the landing will be 69.7804 feet.

Have a nice day!

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Step-by-step explanation:

This is a triangle so it interior degrees will add up to 180.

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We can find OAC by using the triangle interior theorem,

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vova2212 [387]

Given:

second term = 18

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\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}

Hence, we have:

\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\  \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}

Divide the expression for the fifth term by the expression for the second term:

\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}

Substituting the value of r into any of the expression:

\begin{gathered} ar\text{ =  18} \\ a\text{ }\times\text{ 2 =  18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}

Hence, the explicit rule for the sequence is:

a_n\text{ = 9\lparen2\rparen}^{n-1}

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Step-by-step explanation:

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- 2a = 8 ( divide both sides by - 2 )

a = - 4

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