If you're talking about connecting to the internet internet, it would be the PS2. You could buy an adapter for an ethernet cable to allow for online play.
Answer:
Following are the program in the Python Programming Language.
#define function
def Transfer(S, T):
#set for loop
for i in range(len(S)):
#append in the list
T.append(S.pop())
#return the value of the list
return T
#set list type variable
S = ["a","b","c","d"]
#print the values of the list
print(S)
#set the list empty type variable
T=[]
#call the function
T = Transfer(S, T)
#print the value of T
print(T)
<u>Output:</u>
['a', 'b', 'c', 'd']
['d', 'c', 'b', 'a']
Explanation:
Here, we define the function "Transfer()" in which we pass two list type arguments "S" and "T".
- Set the for loop to append the values in the list.
- Then, we append the value of the variable "S" in the variable "T".
- Return the value of the list variable "T" and close the function.
- Then, set the list data type variable "S" and initialize the elements in it and print that variable.
- Finally, we set the empty list type variable "T" and store the return value of the function "Transfer()" in the variable "T" then, print the value of the variable "T".
Answer:
b. lw $t4, 4($t0)
c. add $t3, $t5, $t4
Explanation:
Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.
Can you prove more information?
Answer:
def isAnagram(s1, s2):
list1=s1
list2=s2
sortedlist1 = sorted(list1)
sortedlist2 = sorted(list2)
if sortedlist1 == sortedlist2:
print(list1+ " and "+list2+ " are anagram")
else:
print(list1+ " and "+list2+ " are not anagram")
Explanation:
Here is a call to the function isAnagram():
list1 =input("Enter String1 ")
list1 =input("Enter String2 ")
isAnagram(list1,list2)
Attached is the run and output for this program
