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dusya [7]
3 years ago
11

Solve x^2-7x+12=0 by using the quadratic formula

Mathematics
1 answer:
Katarina [22]3 years ago
4 0
The answer is : x=4, 3
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John joined a fitness club that has a membership fee of $30 +25 per month. Mary’s club has a fee of 50 and charges 15 per month.
zmey [24]
Just solve until the answers are the same


25 times x plus 30 for John

15 times x plus 50 for Mary

8 0
3 years ago
FIND THE AREA OF THE FIGURE BELOW
Romashka [77]

Answer:

220 squared units

Step-by-step explanation:

first, find the area of the rectangle by multiplying 8 by 20. Then, fin the area of the triangle by multiplying 6 by 20 and then dividing the result by 2.

8*20=160

6*20=120

120/2=60

Finally, add them together and you get 220 units squared.

7 0
2 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
Read 2 more answers
Using Triangle Similarity Theorems (6)
Fantom [35]

Answer:

DC = 3

Step-by-step explanation:

Based on triangle similarity theorem, we would have the following equation:

\frac{AD}{AC} = \frac{AE}{AB}

Plug in the values

\frac{9}{9 + DC} = \frac{12}{12 + 4}

\frac{9}{9 + DC} = \frac{12}{16}

\frac{9}{9 + DC} = \frac{3}{4}

Cross multiply

3(9 + DC) = 9×4

27 + 3DC = 36

Subtract 27 from each side

3DC = 36 - 27

3DC = 9

Divide both sides by 3

DC = 9/3

DC = 3

6 0
2 years ago
Given cos 0 = 11/6 and angle 0 is in Quadrant I, what is the exact value of sin 0 in
user100 [1]

1 = sin²0 + cos²0

sin²0 = 1 - cos²0

sin²0 = 1 - 11/36

sin²0 = 25/36

sin 0 = 5/6 or -5/6

In the first quadrant, the values for sin, cos and tan are positive.

sin0 = 5/6

8 0
3 years ago
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