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vredina [299]
3 years ago
12

What is the value of this quadratic function. 4x^2+88x

Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

Answer:

x = 0 or x = -22

Step-by-step explanation by completing the square:

Solve for x:

4 x^2 + 88 x = 0

Divide both sides by 4:

x^2 + 22 x = 0

Add 121 to both sides:

x^2 + 22 x + 121 = 121

Write the left hand side as a square:

(x + 11)^2 = 121

Take the square root of both sides:

x + 11 = 11 or x + 11 = -11

Subtract 11 from both sides:

x = 0 or x + 11 = -11

Subtract 11 from both sides:

Answer:  x = 0 or x = -22

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Which land forms are formed by wind deposition in the desert region?​
Elena L [17]

Answer:

Sand Dune Landforms

Sand dunes (both active and stabilized by vegetation) can be found along beaches, and in arid or semi-arid regions. Dunes are mounds of loose sand created by wind and are the most well known aeolian features

8 0
2 years ago
Read 2 more answers
Which of the following points solves the system shown below?
IrinaVladis [17]

Answer:

(3,6)

Step-by-step explanation:

Collect like terms

y -5x = -9

y + 2x = 12

Using elimination method

Subtract equation 2 from equation 1

y - 5x = -9

y + 2x = 12

---------------

0. -7x = -21

Divide both sides by -7

-7x = -21

---- -----

-7 -7

x = 3

Substitute x=3 into equation 1

y = 5(3) - 9

y = 15 - 9

y = 6

Solution is (x,y) = (3,6)

6 0
3 years ago
X+3<9 answer pls 2x+5<12
diamong [38]

Answer:

first one: x<9 second: x<3.5 or 7/2

Step-by-step explanation:

first: substract 3 from both sides

second: substract 5 and then divide by 2

7 0
3 years ago
Find the conjugate of -2 + 3i.
Charra [1.4K]

Answer:

- 2 - 3i

Step-by-step explanation:

given a complex number a + bi

then the conjugate is a - bi

The real part a remains unchanged while the sign of the imaginary part is reversed.

the conjugate of - 2 + 3i is - 2 - 3i


4 0
3 years ago
Find the matrix product, if possible.  Show your work please
steposvetlana [31]
\left[\begin{array}{ccc}-1&3\\5&4\end{array}\right] \cdot  \left[\begin{array}{ccc}0&-2&6\\1&-3&2\end{array}\right]\\\\=  \left[\begin{array}{ccc}(-1)(0)+(3)(1)&(-1)(-2)+(3)(-3)&(-1)(6)+(3)(2)\\(5)(0)+(4)(1)&(5)(-2)+(4)(-3)&(5)(6)+(4)(2)\end{array}\right]\\\\=  \left[\begin{array}{ccc}0+3&2-9&-6+6\\0+4&-10-12&30+8\end{array}\right]\\\\  =\left[\begin{array}{ccc}3&-7&0\\4&-22&38\end{array}\right]

3 0
3 years ago
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