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tankabanditka [31]
3 years ago
7

PLEASE ANSWERR!! WILL MARK BRAINLIEST!!

Mathematics
1 answer:
telo118 [61]3 years ago
6 0

Answer:

2nd one

Step-by-step explanation:

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10. WEATHER On average, the circular eye of a hurricane is about 15 miles in diameter. Gale winds can affect an area up to 300 m
kykrilka [37]

The equation to represent a possible boundary of the hurricane's eye is (x - 80)² + (y - 26)² = 7.5²

<h3>Circle Equation</h3>

The standard equation of a circle is given by:

(x - h)² + (y - k)² = r²

Where (h, k) is the center of the circle and r is the radius.

Given that diameter = 15 miles, hence radius = 15/2  = 7.5. Also, center = (80, 26)

The equation of circle is:

(x - 80)² + (y - 26)² = 7.5²

The equation to represent a possible boundary of the hurricane's eye is (x - 80)² + (y - 26)² = 7.5²

Find out more on Circle Equation at: brainly.com/question/1559324

5 0
2 years ago
What is the circumference of a circle p PB=29m
Diano4ka-milaya [45]
What you mean by "p PB" is almost totally unclear.

If the diameter of the circle is 29 m, then the circumference is 29 pi m.
If the radius                         is 29 m, then the circumf. is 2(29 m) pi, or 58 pi m.
8 0
3 years ago
Read 2 more answers
Alan is arranging 3 different stuffed toys in a row on a shelf. Create a sample space for the arrangement of a teddy bear (T), a
elena55 [62]

Answer:

teddy bear (Tb)

kitten (kit)

elephant (big ears)

5 0
3 years ago
Read 2 more answers
Round 354,738 to the nearest thousand?
Alchen [17]
Your answer is 400,000.

Hope this helps!
7 0
3 years ago
9. Hallar el perímetro de la figura sombreada.
STatiana [176]

Respuesta:

Perímetro de la parte sombreada = (6pi + 24)

Explicación paso a paso:

Encuentra el diagrama adjunto

Primero necesitamos encontrar el perímetro de los semicírculos externos que sobresalen

Diámetro del semicírculo = 1/2 de la longitud del lado del cuadrado

Diámetro del semicírculo = 1/2 × 6 m = 3 m

Perímetro de los 4 semicírculos = 4 (pi d)

Perímetro de los 4 semicírculos = 4 × 3,14 × 3

Perímetro de los 4 semicírculos exteriores = 1

2pi cm

Para la parte interior sombreada = Perímetro de todo el cuadrado - Perímetro de semicírculo (2 cuadrantes)

Perímetro del cuadrado entero = 4 (6) = 24m

Perímetro de los 2 cuadrantes = pi d

Perímetro de los 2 cuadrantes = 6pi cm

Para la parte sombreada interior, perímetro = 24-6pi

Perímetro de la parte sombreada = 12pi + 24-6pi

Perímetro de la parte sombreada = (6pi + 24) cm

7 0
3 years ago
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