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bija089 [108]
2 years ago
11

the diagram, JG = 5 cm and GE = 10 cm. Based on this information, can G be a centroid of triangle HJK?

Mathematics
2 answers:
Semenov [28]2 years ago
8 0

Answer:

the answer is B on e2020

Step-by-step explanation:

just took the answer.

SIZIF [17.4K]2 years ago
4 0
Point G cannot be a centroid because GE is wider that JG or JG is shorter than GE. So in this diagram GE is wider than JG with 10 cm and 5 cm respectively based on this information Point G cannot be a centroid of triangle HJK. So the answer is point G cannot be a centroid because JG is shorter than GE.
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Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

3 0
2 years ago
What is 33 divided by 2244
olchik [2.2K]

Answer:

0.01470588235

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
27^x −1 = 9^3x−7 what is X
tigry1 [53]

x is \frac{11}{3}

Step-by-step explanation:

Let us revise some rules of exponents

  • (a^{n})(a^{n})=a^{m+n}
  • \frac{a^{m}}{a^{n}}=a^{m-n}
  • (a^{m})^{n}=a^{mn}
  • a^{m}=a^{n} , then m = n

∵ 27^{x-1}=9^{3x-7}

- Factorize 27 and 9

∵ 27 = 3 × 3 × 3

∴ 27 = 3³

∵ 9 = 3 × 3

∴ 9 = 3²

Substitute them in the equation

∴ (3^{3})^{x-1}=(3^{2})^{3x-7}

- Use the third rule to simplify each side

∴ (3)^{3x-3}=(3)^{6x-14}

- Use the fourth rule

∵ The bases of the two sides are equal

∴ Their exponents are equal

∴ 3x - 3 = 6x - 14

- Subtract 6x from both sides

∴ -3x - 3 = -14

- Add 3 to both sides

∴ -3x = -11

Divide both sides by -3

∴ x = \frac{11}{3}

x is \frac{11}{3}

Learn more:

You can learn more about equations in brainly.com/question/4934417

#LearnwithBrainly

3 0
3 years ago
A projectile is thrown upward so that its distance above the ground after t seconds is h = -16t2 + 608t.After how many seconds d
Nat2105 [25]
The question is asking you to find the axis of symmetry, which is the x-value of the vertex. In order to do that you need to factor the function to find the zeros and add the zeros together and divide by two to find the axis of symmetry.
y=-16x^2+608x
y=-16x(x-38)
Zeros: x=0 and x=38
38/2=19
Therefore it takes 19 seconds for the projectile to reach its maximum height.
Hope this helps!
3 0
3 years ago
What percentage of the semi circle is shaded? <br>​
mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0
2 years ago
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