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Luda [366]
3 years ago
5

What is the solution to this equation?

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer:

C

Step-by-step explanation:

-0.2(x-20)=44-x

Divide both sides by -0.2:

x-20=-220+5x

Subtract x from both sides:

-20=-220+4x

Add 220 to both sides:

200=4x

x=50, or answer choice C. Hope this helps!

Anna007 [38]3 years ago
7 0

x = 50

Isolate the variable by dividing each side by factors that don't contain the variable. x=50 this is helpful

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First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

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\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • x = 35°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:4x + 1 + x + 4 = 180

[ by linear pair ]

\qquad❖ \:  \sf \:5x + 5 = 180

\qquad❖ \:  \sf \:5(x + 1) = 180

\qquad❖ \:  \sf \:x + 1 = 180 \div 5

\qquad❖ \:  \sf \:x + 1 = 36

\qquad❖ \:  \sf \:x = 36 - 1

\qquad❖ \:  \sf \:x = 35

\qquad \large \sf {Conclusion}  :

  • x = 35°
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