Answer:
I'm pretty sure it's 5 hours tutoring and 7 hours landscaping.
Opposite angles of an inscribed quadrilateral are supplementary, so it is true that ...
... B. m∠A + m∠C = m∠B + m∠D . . . . . = 180°
Answer:
The slope of the line is 
Step-by-step explanation:
For any line 
, a line that is perpendicular to it is 
.
Therefore the slope of the perpendicular line is 
.
For our case 
therefore the slope of the prependicular is the reciprocal of 
multiplied by 
Answer:
6.83 units
Step-by-step explanation:
Let the height of the original pyramid be represented by h. Then the cut off top has a height of (h -2). The scale factor for the area is the square of the scale factor for height, so we have ...
(height ratio)^2 = 1/2
((h -2)/h)^2 = 1/2
(h -2)√2 = h . . . . . . square root; multiply by h√2
h(√2 -1) = 2√2 . . . . add 2√2 -h
h = (2√2)/(√2 -1) ≈ 6.8284 . . . units
The altitude of the original pyramid is about 6.83 units.
Answer:
Step-by-step explanation:
since -1≤sin2x≤1 no x values would satisfy the equation
