To calculate, 1st convert <span>1,750 USD to CLP by multiplying it with exchange rate 496.50 CLP/1USD. Total is CLP 868,875. Then by subtracting the expenses in CLP (CLP 217,513), remaining is CLP 651,362. Convert it to VEF by multiplying the exchange rate 0.1283 VEF/1 CLP. Resulting is </span><span> VEF 83,569.74. Then, subtract it with the expenses in VEF (VEF 31,422.19). Remaining VEF is </span><span> VEF 45,147.55. Next, convert it to PYG by multiplying it with 1,063.95 PYG/1 VEF. Result is </span><span> PYG 48,034,740.72. Next, subtract it with the expenses in PYG (PYG </span>12,857,441.39). Difference is PYG 35,177,299.33. Lastly, convert if to USD by multiplying it with 0.00002186 USD/1 PYG. Final answer is <span> USD <span>768.98.</span></span>
Answer:
24
Step-by-step explanation:
I think its 24 because 64÷20=40
Answer:
Profit = $(700 - 42x - 56y)
Step-by-step explanation:
For large candles, the selling price is $10 and its making cost is $x.
So, by selling a large candle the profit is $(10 - x)
Again for small candles, the selling price is $5 and its making cost is $y.
So, by selling a small candle the profit is $(5 - y)
Therefore, in a sell of 42 large candles and 56 small candles the total profit will be, P = 42 (10 - x) + 56 (5 - y)
⇒ P = 420 - 42x + 280 - 56y {Applying distributive property}
⇒ P = $(700 - 42x - 56y) (Answer)
Answer:
A. 1
B. 
.
Step-by-step explanation:
We have been given an equation of a line 
.
A. We know that slope of parallel lines is always equal,
We can see that slope of our given line is 1, therefore the slope of the line parallel to our given line would be 1.
B. We know that the product of slopes of two perpendicular lines is .
Let m represent slope of perpendicular to our given line, then:
Therefore the slope of the line perpendicular to our given line would be .
For this case, we have that the equation of the position is given by:
To find the velocity, we must derive the equation from the position.
We have then:
Then, we evaluate the derivative for time t = 8.
We have then:
Answer:
the instantaneous velocity at t = 8 is:
