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Kitty [74]
3 years ago
10

Halla el área de un triángulo equilátero de 54 cm de perímetros

Mathematics
1 answer:
adoni [48]3 years ago
5 0

Answer:

Area of equilateral triangle = 81√3 cm²

Step-by-step explanation:

Given:

Perimeter of an equilateral triangle = 54 cm

Find:

Area of equilateral triangle

Computation:

Perimeter of an equilateral triangle = 3 x Side

54 = 3 x Side

Side of equilateral triangle = 54 / 3

Side of equilateral triangle = 18 cm

Area of equilateral triangle = [√3/4]side²

Area of equilateral triangle = [√3/4][18]²

Area of equilateral triangle = [√3/4][324]

Area of equilateral triangle = [√3][81]

Area of equilateral triangle = 81√3 cm²

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What complex number is represented by the polar coordinates (4, -pi/4)
nexus9112 [7]

Answer:

\displaystyle \large{z=2\sqrt{2} -2 \sqrt{2}i}

Step-by-step explanation:

A complex number is defined as z = a + bi. Since the complex number also represents right triangle whenever forms a vector at (a,b). Hence, a = rcosθ and b = rsinθ where r is radius (sometimes is written as <em>|z|).</em>

Substitute a = rcosθ and b = rsinθ in which the equation be z = rcosθ + irsinθ.

Factor r-term and we finally have z = r(cosθ + isinθ). How fortunately, the polar coordinate is defined as (r, θ) coordinate and therefore we can say that r = 4 and θ = -π/4. Substitute the values in the equation.

\displaystyle \large{z=4[\cos (-\frac{\pi}{4}) + i\sin (-\frac{\pi}{4})]}

Evaluate the values. Keep in mind that both cos(-π/4) is cos(-45°) which is √2/2 and sin(-π/4) is sin(-45°) which is -√2/2 as accorded to unit circle.

\displaystyle \large{z=4\left(\frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2}i \right)}\\\\\displaystyle \large{z=2\sqrt{2} -2 \sqrt{2}i}

Hence, the complex number that has polar coordinate of (4,-45°) is \displaystyle \large{z=2\sqrt{2} -2 \sqrt{2}i}

3 0
2 years ago
Find cosine of angle a ​
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Answer:

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Step-by-step explanation:

6 0
3 years ago
David made fruit punch for his party but accidentally tripped and spilled 5/12 of the punch. How much of the punch was left?
Radda [10]
7/12 of the punch was left; 12-5=7
4 0
3 years ago
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Which of the following is a solution of z^5 = 1 + √3 i?
nordsb [41]

Answer:

Option 2 is right

Step-by-step explanation:

Given that

z^5=1+\sqrt{3} i

We can write this in polar form with modulus and radius

|z^5|= \sqrt{1+3} =2\\tan of Angle t =\sqrt{3} \\

Hence angle = 60 degrees and

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Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360

Using Demoivre theorem we get 5th root would be

5th root of 2 multiplied by 1/5 th of 60, 420, 780,....

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Out of these only 2nd option suits our answer

Hence answer is Option 2.

8 0
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(69 POINTS!!!)
marshall27 [118]

Answer:

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Step-by-step explanation:

6 0
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