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3 years ago

Evaluate -3+y/5 when y= -2.5

Mathematics

2 answers:

guapka [62]3 years ago

7 0

-1.1. You have to add -2.5 and -3 which gives you -5.5. When you divide -5.5 over 5 that gives you -1.1.

Thepotemich [5.8K]3 years ago

3 0

(-3-2,5)/5 = (-5,5)/5 = -1,1

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Triangle PQR is reflected over the line y = x.

goblinko [34]

Answer:

-2,4

Step-by-step explanation:

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3 years ago

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At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the qua

Nady [450]

Answer:

1) The demand equation is $x=-0.25p+300$

2) The price when no consumers willing to buy this commodity is $1200.

3) The quantity of the commodity would consumers take if it was free is 300 pounds.

Step-by-step explanation:

Given : At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the quantity demanded decreases by 14 pounds.

To find :

1) The demand equation ?

2) At what price are no consumers willing to buy this commodity?

3) According to the above model, how many pounds of this commodity would consumers take if it was free?

Solution :

1) According to question,

p is the unit price and x is the quantity demanded for this commodity in pounds.

Let, $p_1=\$900$ and $x_1=75\text{ pounds}$

and $p_2=\$956$ and $x_2=75-14=61\text{ pounds}$

To find the demand equation we apply two point slope form,

$(x - x_1)=\frac{(x_2-x_1)}{(p_2-p_1)}\times(p-p_1)$

Substitute the values,

$(x - 75)=\frac{61-75}{956-900}\times(p-900)$

$(x - 75)=\frac{-14}{56}\times(p-900)$

$(x - 75)=\frac{-1}{4}\times(p-900)$

$x-75=-\frac{1}{4}p+225$

$x=-\frac{1}{4}p+300$

$x=-0.25p+300$

The demand equation is $x=-0.25p+300$

2) For no consumers,

Substitute x=0 in demand equation,

$0=-0.25p+300$

$0.25p=300$

$p=\frac{300}{0.25}$

$p=1200$

The price when no consumers willing to buy this commodity is $1200.

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Substitute p=0 in demand equation,

$x=-0.25(0)+300$

$x=300$

The quantity of the commodity would consumers take if it was free is 300 pounds.

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3 years ago

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Answer:

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3 years ago

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1. Find the product. Simplify. 13/14 of 10/9. A. 15/42 B. 5/21 C. 2/7 D. 5/6 2. Andy has 5 pots, and each pot can hold 3/8 pound

Rufina [12.5K]

1) Resultant fraction: $\frac{65}{63}$

2) Total soil: $1\frac{7}{8}$ pounds

3) Result of the product: $\frac{35}{2}$

Step-by-step explanation:

In this problem, we want to find the product between the two fractions

$\frac{13}{14}$

and

$\frac{10}{9}$

In order to find this product, we have to multiply the numerators of each fraction and the denominators of each fraction. We get:

$\frac{13}{14}\cdot \frac{10}{9}=\frac{13\cdot 10}{14\cdot 9}=\frac{130}{126}$

Now we simplify, dividing both numerator and denominator by 2:

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And the fraction cannot be further simplified.

Here we have:

n = 5 (number of pots that Andy has)

$s=\frac{3}{8}$ (amount of soil (in pounds) that each pot can contain)

In order to find the amount of soil that Andy needs to fill all the pots, we have to multiply the number of pots (n) by the amount of soil that each pot can contain (s).

If we do so, we find:

$t=n \cdot s = 5 \cdot \frac{3}{8}=\frac{5\cdot 3}{8}=\frac{15}{8}$