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1 answer:
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Answer:
y = negative (2) Superscript x Baseline + 3
Step-by-step explanation:
An exponential function has a range of y > 0. In order for it to have a range of y < 3, it must be reflected across the x-axis (given a negative multiplier) and must be translated upward 3 units.
That is, for some exponential function y = b^x, you must have something of the form ...
y = -a·b^x +3
Only one answer choice has this form:
Y=((square root of 2)+1)
1) (y-1)^2 =2
so we can concludes that y-1 = squareroot of 2
so ((squareeroot of 2+1) - 1)^2 = 2
2)First we can convert 21÷2 fraction to decmial form which is 10.5
so our equation would be (c+1)^2= 10.5
so c+1 is the sqaureroot root of 10.5
so c would be the (square root of 10.5)-1
3)We can again convert those fractions to decimals so 3/2=1.5 and 71/4 =17.75
so our equation would be (e-1.5)^2=17.75
so (e-1.5) is the square root of 17.75
so e=((square root of 17.75)+1)
1) (y-1)^2 =2
so we can concludes that y-1 = squareroot of 2
so ((squareeroot of 2+1) - 1)^2 = 2
2)First we can convert 21÷2 fraction to decmial form which is 10.5
so our equation would be (c+1)^2= 10.5
so c+1 is the sqaureroot root of 10.5
so c would be the (square root of 10.5)-1
3)We can again convert those fractions to decimals so 3/2=1.5 and 71/4 =17.75
so our equation would be (e-1.5)^2=17.75
so (e-1.5) is the square root of 17.75
so e=((square root of 17.75)+1)