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elixir [45]
2 years ago
5

What is the equivalent amount in year ten of an expenditure of $5,000 in year one, $6,000 in year two, and amounts increasing by

$1,000 per year through year ten?
Mathematics
1 answer:
Archy [21]2 years ago
3 0

Answer:

The correct answer is the equivalent amount is $139,059.41

Step-by-step explanation:

According to the scenario, the computation of the equivalent amount in year ten is shown below;

= $5,000 × (P/A, 10%,10) + $1,000 × (P/G, 10%,10)

= $5,000 × 6.1466 + $1,000 × 22.8913

= $30,723 + $22,891.30

= $53,614.30

Now the equivalent amount is

= $53,614.30 × (F/P, 10%,10)

= $53,614.30 × 2.5937

= $139,059.41

Hence, the equivalent amount is $139,059.41

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<em><u>Solution:</u></em>

Let "p" be the number of presale tickets sold

Let "g" be the number of tickets sold at gate

<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>

Therefore,

Presale tickets + tickets sold at gate = 800

p + g = 800 ------ eqn 1

<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>

Therefore,

Number of tickets sold at gate = twice the number of pre-sale tickets - 13

g = 2p - 13 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 2 in eqn 1

p + 2p - 13 = 800

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3p = 800 + 13

3p = 813

p = 271

Thus 271 presale tickets were sold

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3 years ago
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Answer:

Step-by-step explanation:

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Trava [24]
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Now that you have the price for 1 hour including the initial fee, now you need to find the price for each hour after that. Here's how I did that:

I created a graph that looked like this:

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Here's how I figured out the price for each hour:

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Hour 3 (excluding initial price):
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So, looking at the graph, their prices are the same once each instruction reaches 3 hours. ($41.50)

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