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elixir [45]
2 years ago
5

What is the equivalent amount in year ten of an expenditure of $5,000 in year one, $6,000 in year two, and amounts increasing by

$1,000 per year through year ten?
Mathematics
1 answer:
Archy [21]2 years ago
3 0

Answer:

The correct answer is the equivalent amount is $139,059.41

Step-by-step explanation:

According to the scenario, the computation of the equivalent amount in year ten is shown below;

= $5,000 × (P/A, 10%,10) + $1,000 × (P/G, 10%,10)

= $5,000 × 6.1466 + $1,000 × 22.8913

= $30,723 + $22,891.30

= $53,614.30

Now the equivalent amount is

= $53,614.30 × (F/P, 10%,10)

= $53,614.30 × 2.5937

= $139,059.41

Hence, the equivalent amount is $139,059.41

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What is the equation of a line parallel to y=1/2×+6 that passes through (-4,1)
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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

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so we're really looking for the equation of a line whose slope is 1/2 and passes through (-4 , 1)

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=\cfrac{1}{2}(x+4)\implies y-1=\cfrac{1}{2}x+2\implies y=\cfrac{1}{2}x+3

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Step-by-step explanation:

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