Answer: A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin .
Step-by-step explanation:
From the given figure, the coordinates of ΔABC are A(-3,4), B(-3,1), C(-2,1) and the coordinates of ΔA'B'C' are A'(3,1), B'(3,4), C'(2,4).
When, a translation of 5 units down is applied to ΔABC, the coordinates of the image will be
Then applying 180° counterclockwise rotation about the origin, the coordinates of the image will be :-
which are the coordinates of ΔA'B'C'.
Hence, the set of transformations is performed on triangle ABC to form triangle A’B’C’ is " A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin ".
Answer:
It is the graph of g(x) shifted 5 units right and 2 units down.
Step-by-step explanation:
Given : f(x)=log_2(x−5)−2
the parent function g(x)=log_2(x)
To get f(x) , 5 is subtracted from x
If we add any number with x then we shift left
If we subtract any number from x then we shift right
Here 5 is subtracted from x , so we shift 5 units right
Also -2 at the end
If we add any number at the end , then we shift up
if we subtract any number at the end , then we shift down
Here 2 is subtracted at the end , so we shift 2 units down
It is the graph of g(x) shifted 5 units right and 2 units down.
Answer:
where the triangles are........????
Answer:(-2,3.5)
Step-by-step explanation: Add the endpoints and divide by two for the x-values and the y-values