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4 years ago

11

Philip is going on a 400 mile road trip with three friends. He can travel 18 miles for every gallon of gas used. Gas costs $3.59

per gallon. If Philip and his friends want to split the cost of gas evenly, how much should each person pay?

2 answers:

expeople1 [14]4 years ago

8 0

Answer:

well divide the price of the gas by the three friends and you'll get your answer.

ololo11 [35]4 years ago

5 0

Answer:

$19.94 approx

Step-by-step explanation:

Divide 18 into 400, then take that number and multiply by 3.59. Take that answer and divide it by 4 since it's him +3 to get 19.94

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Given the endpoint (-9,3) and (1,8) partition the segment into the ratio 2:3<br>

Sindrei [870]

Answer:

$P = (-5,5)$

Step-by-step explanation:

Let the segments be A and B

$A = (-9,3)$

$B = (1,8)$

$m:n = 2:3$

Required

Determine the endpoints after it is divided into ratios.

<em>Let the point be represented with P</em>

The formula to use is:

$P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

Where

$A = (-9,3)$ ----- $(x_1,y_1)$

$B = (1,8)$ ------ $(x_2,y_2)$

So:

$P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

$P = (\frac{2 * 1 + 3 * -9}{2 + 3},\frac{2 * 8 + 3 * 3}{2 + 3})$

$P = (\frac{-25}{5},\frac{25}{5})$

$P = (-5,5)$

6 0

3 years ago

iren [92.7K]

Hi there,

1)
6 + (w - 10) = 5
6 + w - 10 = 5
- 4 + w = 5
w = 5 + 4

Hence, W = 9

2)
2/3 + y - 1/9 = 7/9
5/9 + y = 7/9
y= 7/9 - 5/9

Hence, Y = 2/9

4)
4x - 3/2x - 15/4 = 3/8
32x - 12x - 30 = 3
20x - 30 = 3
20x = 3 + 30
20x = 33

Hence, the answer is 33/20

5)
0.7(3s + 4) - 1.1s = 7.9
2.1s + 2.8 - 1.1 = 7.9
s + 2.8 = 7.9
s = 7.9 - 2.8

Hence, the answer is 5.1

Hope this all helps :)

8 0

3 years ago

Read 2 more answers

HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME

Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.

Since, the scale factor $\frac{5}{3}$ is greater than 1, the image is enlargement or a stretch.

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor $\frac{5}{3}$

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image $S{}'$ are same.

Now, the distances from the center of the dilation at point S to the other points R and T.

The dilation image will be $\frac{5}{3}$ of each of these distances,

$SR=3$ , so $S{}'R{}'$ =5 ;

$ST=3$ , so $S{}'T{}'=5$

Now, draw the image of RST i.e R'S'T'

Since, $RT=3\sqrt{2}$ [By using hypotenuse of right angle triangle] and $R{}'T{}'=5\sqrt{2}$ .

2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of $\overline{AC}$ i.e $\overline{AB}\cong \overline{BC}$

In the triangle ABD and triangle CBD, we have

$\overline{AB}\cong \overline{BC}$ (SIDE) [Given]

$\overline{BD}\cong \overline{BD}$ (SIDE) [Reflexive post]

Since, there is no included angle in these triangles.

∴ $\Delta ABD$ is not congruent to $\Delta CBD$ .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that $\overline{AD}\cong \overline{CD}$ .

therefore, in the triangle ABD and triangle CBD, we have

$\overline{AB}\cong \overline{BC}$ (SIDE) [Given]

$\overline{AD}\cong \overline{CD}$ (SIDE) [Given]

$\overline{BD}\cong \overline{BD}$ (SIDE) [Reflexive post]

therefore by, SSS postulates $\Delta ABD\cong \Delta CBD$ .

3)

Given that: $\angle1=\angle 3$ are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

$\angle 1$ and $\angle 2$ and $\angle 3$ and $\angle 2$ are linear pair.

By linear pair theorem, $\angle 1$ and $\angle 2$ are supplementary, $\angle 2$ and $\angle 3$ are supplementary.

$m\angle1+m\angle 2=180^{\circ}$

$m\angle2+m\angle 3=180^{\circ}$

Equate the above expressions:

$m\angle 1+m\angle 2=m\angle 2+m\angle 3$

Subtract the angle 2 from both sides in the above expressions

∴ $m\angle 1=m\angle 3$

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.

therefore, $\angle 1\cong \angle 3$ .

3 0

3 years ago

Read 2 more answers

Simplify the following expression

Kay [80]

Answer:

$\frac{98p^{6}}{q}$

Step-by-step explanation:

Distribute the exponents

$(\frac{(7^{-2}p^{-6}q^{-8})}{2q^{-9}} )^{-1}$

$(\frac{q}{98p^{6}} )^{-1}$

Distribute the -1

$\frac{98p^{6}}{q}$

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3 years ago

Which equation is represented by the graph below?

kirill115 [55]

Answer:

y = $\frac{2}{3}x$ + 6

Step-by-step explanation:

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3 years ago