Answer:
Both length and width of 7.25m
Step-by-step explanation:
Let L and W be the length and width of the rectangle, respectively. Since the perimeter is 29, we have the following equation
(L + W)2 = 29
L + W = 29/2 = 14.5
L = 14.5 - W
Also the area of the rectangle would be as the following:
A = LW = W(14.5 - W) = 14.5W - W^2
To find the maximum area possible, we can take the first derivative and set it to 0
A' = 14.5 - 2W = 0
2W = 14.5
W = 14.5 / 2 = 7.25m
L = 14.5 - W = 14.5 - 7.25 = 7.25m
Part A:
We see that this pair of equations has 1 solution. On a graph, the solutions of 2 (or more) lines is where the lines intersect. In this case, since these lines intersect 1 time, they have 1 solution.
Part B:
As previously mentioned, the solutions of multiple lines is where the lines intersect. In this case, since they intersect at (4,4), that is the solution.
<span>a || b
4x + 72 + 2x - 12 = 180
6x + 60 = 180
6x = 180 -60
6x = 120
x = 120/6
x = 20</span>
100 - 45 - 20 (0.2 = 20%) - 12.5 (1/8 = 12.5%) = 22.5%
