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3 years ago

Can you please solve Y=15x? I’m not quite understanding...

Mathematics

1 answer:

GarryVolchara [31]3 years ago

3 0

Can you put more context?

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Yon made contributions to a Traditional IRA over the course of 15 working years. Her contributions averaged $4,000 annually. Yon

Firlakuza [10]

First find the future value of an annuity ordinary using the formula of
Fv=pmt [(1+r)^(n)-1)÷(r)]
Fv future value?
PMT 4000
R 0.05
N 15 years
Fv=4,000×(((1+0.05)^(15)−1)÷(0.05))
Fv=86,314.25

Then deducte the 15% tax bracket from the amount we found to get the effective value of Yon's traditional IRA at retirement
86,314.25−86,314.25×0.15
=73,367.11

7 0

3 years ago

YO SOMEONE HELP PLEASEEEEEEEE

Hitman42 [59]

Nothing further can be done with this topic. Please check the expression entered or try another topic.

log 5 x ( 2 x − 4)=3x+2

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4 years ago

Read 2 more answers

Lisa typed a 165-word paragraph in three minutes. Use the ratio table to

JulsSmile [24]

Answer:

1 minute

Step-by-step explanation:

We can see that Lisa types 165 words in 3 mins.

So she types 55 words in 1 minute.

How did I work that out?

Well, all you really do is $\frac {165}{3}$ which is equal to $\frac{55}{1}$ if you divide top and bottom by 3. Anything divided by 1 is itself.

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2 years ago

If you have 8/12 of pizza, how many thirds do you have?

Deffense [45]

8/12 is equivalent to 2/3.

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4 years ago

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Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an

Harrizon [31]

Answer:

$x^{1}$ wives

$x^{2}$ sacks

$x^{3}$ cats

$x^{4}$ kits

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

$x^{1}$ wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

$x^{2}$ sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

$x^{3}$ cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

$x^{4}$ kits

8 0

3 years ago