Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.
Step-by-step explanation: Speed of Houck family's train = 552m/6hrs
speed of Robert family's train = 744m/8hrs.
Therefore considering Houck speed,
552miles = 6hours
1mile = (6 x 60)/552
= 360/552
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
For Robert
744miles = 8hours
1mile = ( 8 x 60 )/744
= (480/744)minutes
= 0.645
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
Conclusion: Both families were travelling at the same speed/rate.
To get that minutes in hour, just divide by 60 to get concert to hours.
Answer:
42 adults and 196 children went to the zoo
Step-by-step explanation:
Let
x ----> the number of adults
y ----> the number of children
we know that
The total bill for the 238 people from a school trip was $1330
so
----> equation A
----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
the solution is the point (42,196)
see the attached figure
therefore
42 adults and 196 children went to the zoo
23 3/4 rounds because you can take 95 divided by 4 to get 23 3/4 rounds
<h3>
Answer: Choice B</h3>
Reflection along y axis
Translation:
which means we shift 3 units down
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Explanation:
Let's track point A to see how it could move to point A'.
If we were to reflect point A over the vertical y axis, then A(-4,4) would move to (4,4). The x coordinate flips in sign, but the y coordinate stays the same.
The diagram shows that A' is located at (4,1) instead of (4,4). So a y-axis reflection isn't enough to move A to A', but we can shift that reflected point three units down. That will move (4,4) to (4,1) which is exactly where we want to end up. Note how we subtract 3 from the y coordinate and x stays the same. So that explains the notation 
Overall, this points to choice B as the final answer. If we apply these steps to points B and C, you should find that they'll land on B' and C' respectively. Apply this to all of the points on the triangle ABC, and it will move everything to triangle A'B'C'.